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P3 Complex number loci.

Hello,:smile:

Please solve the following...

u = (6-3i)/(1+2i)

i. For complex number z satisfying arg(z-u) = pi/4. , find the least value of |z|.

ii. For complex numbers satisfying |z-(1+u)| = 1, find the greatest possible value of |z|.

Thanks. ...
Original post by methewthomson
Hello,:smile:

Please solve the following...

u = (6-3i)/(1+2i)

i. For complex number z satisfying arg(z-u) = pi/4. , find the least value of |z|.

ii. For complex numbers satisfying |z-(1+u)| = 1, find the greatest possible value of |z|.

Thanks. ...


First write u in the form

u=a+bi u = a+bi

It should then be clear how to draw the sketches
(edited 11 years ago)
Original post by Indeterminate
First write u in the form

u=a+bi u = a+bi

It should then be clear how to draw the sketches



Thank you for the reply.

Yes, I had some idea that first it should be written in a+bi form. But what is next? That is what I don't get....

Could you please solve it out....perhaps with graphical illustration...
thanks again.
Original post by methewthomson
Thank you for the reply.

Yes, I had some idea that first it should be written in a+bi form. But what is next? That is what I don't get....

Could you please solve it out....perhaps with graphical illustration...
thanks again.


Well, take

z=x+iyz=x+iy

and draw the half-line representing arg(zu)arg(z-u)

Deduce that tan(π4)=......=1\tan(\frac{\pi}{4}) =...... = 1

As a further hint, you will need to find the minimum value of the quadratic

z2=....|z|^2 = ....

and then take the square root of that.
(edited 11 years ago)
Original post by Indeterminate
Well, take

z=x+iyz=x+iy

and draw the half-line representing arg(zu)arg(z-u)

Deduce that tan(π4)=......=1\tan(\frac{\pi}{4}) =...... = 1

As a further hint, you will need to find the minimum value of the quadratic

z2=....|z|^2 = ....

and then take the square root of that.


Thank you again for replying.:smile:
Actually, I'm bad at loci drawings and that is why I could not draw the half line representing arg(zu)arg(z-u). And why do we draw a half line?Could you plzzzz explain?

u = 3i in our case. That is okay. But the next steps I don't understand.
Reply 5
Original post by methewthomson
Thank you again for replying.:smile:
Actually, I'm bad at loci drawings and that is why I could not draw the half line representing arg(zu)arg(z-u). And why do we draw a half line?Could you plzzzz explain?

u = 3i in our case. That is okay. But the next steps I don't understand.


u = -3i

Can you draw easier loci?

arg(z)=π3arg(z)=\frac{\pi}{3} for example.
Reply 6
You would get b+3=a. (1)
if u assume a+ib as z
now you have to minimise a^2 +b^2 =f(x)^2
so put a from 1 and then differentiate to get b then find ur answer.
Reply 7
Original post by Gifted
You would get b+3=a. (1)
if u assume a+ib as z
now you have to minimise a^2 +b^2 =f(x)^2
so put a from 1 and then differentiate to get b then find ur answer.


I can't say I understand what you're trying to do there.

The question certainly doesn't require any differentiation.

The thread title refers to loci. Once the correct loci are sketched a little bit of high school maths is all that is needed.
Original post by BabyMaths
u = -3i

Can you draw easier loci?

arg(z)=π3arg(z)=\frac{\pi}{3} for example.



Yes, I know how to draw that, but just that. I don't know how to draw the complex type.

Can you plz explain the question I put on this thread?
Reply 9
Original post by methewthomson
Yes, I know how to draw that, but just that. I don't know how to draw the complex type.

Can you plz explain the question I put on this thread?


You're trying to do a sketch for arg(z+3i)=π4arg(z+3i)=\frac{\pi}{4}.

Can you sketch arg(w)=π4arg(w)=\frac{\pi}{4}?

Can you then use the relationship between z and w, namely z=w-3i?
Original post by BabyMaths
You're trying to do a sketch for arg(z+3i)=π4arg(z+3i)=\frac{\pi}{4}.

Can you sketch arg(w)=π4arg(w)=\frac{\pi}{4}?

Can you then use the relationship between z and w, namely z=w-3i?


Thank you:smile: so very much for replying again.

Yes I can sketch easily arg(w)=π4arg(w)=\frac{\pi}{4}. But how will I find the smallest value of w so that z turns out to be smallest, giving smallest modulus???

Could you plz solve the question step by step?Your manner of explanation is really good.

Plz help me as I lose lots of marks on such questions...
thanks....
Reply 11
Original post by methewthomson
Thank you:smile: so very much for replying again.

Yes I can sketch easily arg(w)=π4arg(w)=\frac{\pi}{4}. But how will I find the smallest value of w so that z turns out to be smallest, giving smallest modulus???

Could you plz solve the question step by step?Your manner of explanation is really good.

Plz help me as I lose lots of marks on such questions...
thanks....


Post your sketch(es).

I'd like to see them before I say any more.
Original post by BabyMaths
Post your sketch(es).

I'd like to see them before I say any more.


Okay, here is the sketch you asked me to draw:
untitled.jpg
(edited 11 years ago)
Reply 13
Original post by methewthomson
...


Try to re-upload your picture, doesn't seem to be working for me.
Original post by Joshmeid
Try to re-upload your picture, doesn't seem to be working for me.


Now you will be able to see a small picture. Open the picture in a new window to increase its size.
Reply 15
Original post by methewthomson
Now you will be able to see a small picture. Open the picture in a new window to increase its size.


Ok in that image, you've drawn argz=π4\arg{z} = \frac{\pi}{4}. (ignoring the -3i and 3 marked on the axis.)

This is the half-line starting from the origin with an angle of π4\frac{\pi}{4}.

The argument is written in the form arg(za)=θ\arg{(z - a)} = \theta.

In your case we have arg(z+3i)=θ\arg{(z + 3i)} = \theta, which can be re-written as arg(z3i)=θ\arg{(z - -3i)} = \theta.

We can then represent this on an argand diagram starting at the point (0, -3), with an angle of θ\theta from the positive x-axis.


Now if you understand that, can you make another sketch of argz4+2i=3π4\arg{z - 4 + 2i} = \frac{3\pi}{4}.
(edited 11 years ago)
Reply 16
Original post by Joshmeid
Ok in that image, you've drawn argz=π4\arg{z} = \frac{\pi}{4}.


He's drawn arg(w)=pi/4 as I asked him.

Now, if w=z+3i you have z=w-3i. Just sketch it in 3i below w.
Reply 17
Original post by BabyMaths
He's drawn arg(w)=pi/4 as I asked him.

Now, if w=z+3i you have z=w-3i. Just sketch it in 3i below w.


I attempted to move away from that to prevent confusion later on when he arrives at transformations from z to w plane but feel free to continue.
Original post by BabyMaths
He's drawn arg(w)=pi/4 as I asked him.

Now, if w=z+3i you have z=w-3i. Just sketch it in 3i below w.



Should I sketch z in 3i below? At what angle? Parallel to w?
If possible please draw a diagram.
Thanks.
Original post by Joshmeid
I attempted to move away from that to prevent confusion later on when he arrives at transformations from z to w plane but feel free to continue.


Thank you for all your efforts.

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