C2/FP1 sequence

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I think Ive clocked onto something..
So if I consider the sequence formed by the left of the product of the terms it forms a sequence 1,3,5 etc and same for the right, 2,4,6,8 etc.
The nth term for both of those is (2n-1) and 2n respectively, so can I multiply them together to form (2n-1)2n? It works! :cool:

Good.

Reply 21

UKBrah

Original post by Mr M

Good.

How would one find the general term of a sequence like (3 x 9), (7 x 21), (11 x 34) etc.. is it even possible?

thanks for helping me btw

Reply 22

Mr M

Study Forum Helper

Original post by UKBrah

How would one find the general term of a sequence like (3 x 9), (7 x 21), (11 x 34) etc.. is it even possible?

thanks for helping me btw

Did you mean (3 x 9), (7 x 21) (11 x 33) as this is easy?

Or were you just typing random numbers?

Reply 23

UKBrah

Original post by Mr M

Did you mean (3 x 9), (7 x 21) (11 x 33) as this is easy?

Or were you just typing random numbers?

Yeah I wrote random numbers, is it possible to find an rth term for a sequence like that. Since I lack the intuition to see the rth term, I would have to use the method I used above.

Reply 24

Mr M

Study Forum Helper

Original post by UKBrah

Yeah I wrote random numbers, is it possible to find an rth term for a sequence like that. Since I lack the intuition to see the rth term, I would have to use the method I used above.

There isn't a general rule for random numbers!

In general you can look for a pattern in the first numbers and a different pattern in the second numbers. In the modified version I gave you both sets of numbers form arithmetic sequences.

Reply 25

UKBrah

Original post by Mr M

Thanks dude I find that so cool.
The product of the nth term of the sequence of the left and right of the product is the nth term of the original sequence