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OCR (Not MEI) C2 May 2013 (17.5.13) UO Markscheme

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Reply 40
What was question 7i? Show that...what?
Reply 41
Out of interest, am I the only one who put 19/10 as the area on q7ii)? Everyone seems to have got 37/30 and I'm one of only two people I know who got 19/10, but I can't see what I did wrong :frown:
Reply 42
Original post by chuckynoriss
7ii) how is it 37/30 because you do the integration of curve- tangent from 1 to 4 and 3/2( 1.5) is bigger than 1 so lower limit is 1


The line y=3x-5 crosses the x axis at i think it was (5/3) not one, so it you have to intergrate between 4 and 5/3 instead, which gives the area under the line as 8.1666 :smile: Hope that helps
Reply 43
What was question 3ii. ??
Reply 44
Thanks :smile: do you reckon I'll lose one accuracy mark if I integrated between 4 and 1?
Reply 45
probalby - and maybe one for the answer also- but you should hopefully get all the method marks :smile:
Reply 46
Original post by Hannburger
Hi, what was question 5?? (:


Added question paper
Reply 47
Original post by Paribas01
What was question 3ii. ??


Added question paper
Reply 48
Yeah, I suppose so :s-smilie: thanks again!
Reply 49
Original post by Rrobba
What was question 7i? Show that...what?

Show that 1.3^n > 1.52... Something along those lines can't remember exact no's
Reply 50
Original post by sugartown
Can someone explain why the first one was 6.3 and not 9.56 or something? I got 6.3 before I x the bracket and then 6.3 x 3/2? So confused and feel a bit stupid considering it was such easy marks


I got 9.56 first time, but think I made a mistake so it's 6.39. The start of trapezium rule is 1/2 x h (h=width, in question given as 2) so it's 2/2 (=1) x6.39
Reply 51
Show that 1.3^N_< 91 I think, can't remember which way around the inequality sign was
Reply 52
Original post by tgtips372
Hey :smile: the reason you don't multiply the 6.3 by 3/2 is because the trapezium starts with h/2, there were 3 strips but the width of each strip was 2, so the h/2 was equal to 2/2 so basically it stays as 6.3. Hope that helps! :smile:


Ohhhh so I put 3/2 rather than 2/2 which is obviously 1! Argh so annoying! Think I probably would have got a B anyway as the paper did not go my way so didn't make too much of a difference!
Reply 53
I think I got >63 , does anyone know the highest grade boundaries for c2 there have been in previous years?
Reply 54
Original post by Good@Math
I got 9.56 first time, but think I made a mistake so it's 6.39. The start of trapezium rule is 1/2 x h (h=width, in question given as 2) so it's 2/2 (=1) x6.39


Argh wish I had looked back at it and realised! Thanks for the help
Reply 55
Since there's not one in the OP:
Worked Solution to 8ii)
ax=4bx[br]xlog2a=2+xlog2b[br]x(log2ab)=2[br]as ab=2b=2a[br]x(log2a22)=2[br]x=2log2a1 a^x = 4b^x[br]\Rightarrow x\log_2a = 2+x\log_2b [br]\Rightarrow x(\log_2\frac{a}{b}) =2[br]\mathrm{as} \ ab=2 \Rightarrow b=\frac{2}{a}[br]\Rightarrow x(\log_2\frac{a^2}{2}) = 2[br]\Rightarrow x = \dfrac{2}{log_2a - 1}
(edited 10 years ago)
Reply 56
Original post by joostan
Since there's not one in the OP:
Worked Solution to 8ii)
ax=4bx[br]xlog2a=2+xlog2b=x(log2ab)[br]as ab=2b=2a[br]x(log2a22)=2[br]x=2log2a1 a^x = 4b^x[br]\Rightarrow x\log_2a = 2+xlog_2b = x(\log_2\frac{a}{b})[br]\mathrm{as} \ ab=2 \Rightarrow b=\frac{2}{a}[br]\Rightarrow x(\log_2\frac{a^2}{2}) = 2[br]\Rightarrow x = \dfrac{2}{log_2a - 1}


same method i used :smile:
Reply 57
Dont mean to be disrespectful to anyone's previous posts but I think a lot of people are mistaken on the grade boundaries for this paper. I am myself quite an able mathematician, scoring 96UMS on Core 1, and i did struggle with some aspects of the paper, especially 8ii. bearing in mind that most of the people who post on here are ALSO very able, i think we're forgetting that this was actually quite a difficult paper and will undoubtedly catch out the 'less able' candidates that took it, so my money is on 55-57 for an A grade :smile:
Reply 58
Original post by chubuking
same method i used :smile:


Lol - quite a nice q. The C2 I took in jan didn't have a nice logs question :tongue:
Reply 59
Original post by Good@Math
GRADEJan 11June 10Jan 10June 09Jan 09June 08Jan 08June 07Jan 07June 06Jan 06
MSM7575757575757575757575
A*-----------
A6161586065606062n.a.n.a.n.a.
B5454505257525355n.a.n.a.n.a.
C4747434449444648n.a.n.a.n.a.
D4041363741373941n.a.n.a.n.a.
E3335293034303335n.a.n.a.n.a.


yeaaa.png

Thanks

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