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Reply 5660
Original post by UncreativeJ
Physics = prodigious or fascinating


Fail because fascinating starts with F, not p.


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Original post by Jina
Yes omg!!! On the day of spanish and sociology exam, they were munching like rabbits! And guess who kicked me out?!!! Urgh!!! Could've killed her!


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LMAO. I think the warnings only encouraged them to eat it
Reply 5662
Original post by UncreativeJ
LMAO. I think the warnings only encouraged them to eat it


Haha they were hungrryyy! All of them gathered to munch. Lololol


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Original post by Jina
Fail because fascinating starts with F, not p.


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Prodigious because it starts off with a P

Fascinating because its pronunciation starts off with the "ff" sound...

Checkmate.
Reply 5664
Original post by Jina
Ah you know i was kidding. Trying to parr the chinese.

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Or weren't you? :holmes: :lol: You'll never beat the Chinese! Unless fishy fights for your side...
Reply 5665
Original post by Vionar
Or weren't you? :holmes: :lol: You'll never beat the Chinese! Unless fishy fights for your side...


Are you saying i (personally) am incapable of beating the Chinese? -_- Fishy can fight for us but he doesn't like being bengali.


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Original post by Jina
Haha they were hungrryyy! All of them gathered to munch. Lololol


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LMAO. Goro khanii nuinee?


which part of bangladesh is your family from by the way?
Reply 5667
Original post by UncreativeJ
Prodigious because it starts off with a P

Fascinating because its pronunciation starts off with the "ff" sound...

Checkmate.


You tried... I'll let you have it.


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Original post by Jina
Hahaha physics = puke
Chemistry = craap

Btw meet another bengali = anzipanzi... My friend and personal stalker.


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Lucky PRSOM otherwise I would have negged that post.
Reply 5669
Original post by UncreativeJ
LMAO. Goro khanii nuinee?


which part of bangladesh is your family from by the way?


You must translate (rules)... Haha

Be-whoosh oy gesla sooyt dek-ya.

(They became *untranslatable word* upon seeing the sweets)

Erm bishwanath. - villager roots FTW!


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Reply 5670
Original post by Elm Tree
Lucky PRSOM otherwise I would have negged that post.


-_-

Bye.




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Original post by mollyh77
Awh well I'm sure this year'll be better! Are you doing any other CCEA exams?


yeah, all of my exams aree CCEA haha wby?:smile:
Original post by Jina
You must translate (rules)... Haha

Be-whoosh oy gesla sooyt dek-ya.

(They became *untranslatable word* upon seeing the sweets)

Erm bishwanath. - villager roots FTW!


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Haha...yeah! (But it was only humorous in Bengali :frown: )

sooyt dek-ya fagol oy-gisla (Sylheti Bengali: "sweet saw crazy became")

I see how it is...I'm from Beanibazar in that case
Original post by L'Evil Fish
Nope! It's M2 WJEC, and then M1 AQA, so I won't have had to have covered it :lol:


Fine then :wink:

Consider vertical motion:\mathrm{Consider \ vertical \ motion}:

s=ut+12at2s = ut + \frac{1}{2} at^2

0=30tsin45+12(9.81)(t2)0 = 30t \sin 45^{\circ} + \frac{1}{2} (-9.81)(t^2)

15t24.905t2=015t\sqrt{2} - 4.905t^2 = 0

t(1524.905t)=0t(15\sqrt{2} - 4.905t) = 0

t=0, 10002327t = 0, \ \dfrac{1000\sqrt{2}}{327}

Reject t=0 as looking for final time.\mathrm{Reject} \ t=0 \ \mathrm{as \ looking \ for \ final \ time}.

Consider horizontal motion:\mathrm{Consider \ horizontal \ motion}:

s=ut+12at2s = ut + \frac{1}{2} at^2

s=(30cos45)(10002327)+12(0)(10002327)s = ( 30\cos 45^{\circ} ) \left(\dfrac{1000\sqrt{2}}{327} \right) + \frac{1}{2}(0) \left( \dfrac{1000\sqrt{2}}{327} \right)

s=91.7 m     (3 s.f.)s = 91.7 \ \mathrm{m \ \ \ \ \ } (\mathrm{3 \ s.f.})


For max height:\mathrm{For \ max \ height}:

Max s at v=0;\mathrm{Max \ s \ at} \ v=0;

v2=u2+2asv^2 = u^2 + 2as

0=(30sin45)2+2(9.81)(s)0 = (30 \sin 45^{\circ})^2 + 2(-9.81)(s)

s=22.9 m     (3 s.f.)s = 22.9 \ \mathrm{m \ \ \ \ \ } (\mathrm{3 \ s.f.})


:mmm:
Reply 5674
Original post by UncreativeJ
Haha...yeah! (But it was only humorous in Bengali :frown: )

sooyt dek-ya fagol oy-gisla (Sylheti Bengali: "sweet saw crazy became")

I see how it is...I'm from Beanibazar in that case


Hahaha bengali is the funniest language ever. You can speak bengali but must provide translation below. :smile:

Hahaha love your translation. I should do it like that now.

Beanibazaar :frown: haha


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Reply 5675
Original post by Jina
Are you saying i (personally) am incapable of beating the Chinese? -_- Fishy can fight for us but he doesn't like being bengali.


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No, I'm saying that you couldn't beat the joint forces of budey and aurororororae!
Original post by justinawe
Fine then :wink:

Consider vertical motion:\mathrm{Consider \ vertical \ motion}:

s=ut+12at2s = ut + \frac{1}{2} at^2

0=30tsin45+12(9.81)(t2)0 = 30t \sin 45^{\circ} + \frac{1}{2} (-9.81)(t^2)

15t24.905t2=015t\sqrt{2} - 4.905t^2 = 0

t(1524.905t)=0t(15\sqrt{2} - 4.905t) = 0

t=0, 10002327t = 0, \ \dfrac{1000\sqrt{2}}{327}

Reject t=0 as looking for final time.\mathrm{Reject} \ t=0 \ \mathrm{as \ looking \ for \ final \ time}.

Consider horizontal motion:\mathrm{Consider \ horizontal \ motion}:

s=ut+12at2s = ut + \frac{1}{2} at^2

s=(30cos45)(10002327)+12(0)(10002327)s = ( 30\cos 45^{\circ} ) \left(\dfrac{1000\sqrt{2}}{327} \right) + \frac{1}{2}(0) \left( \dfrac{1000\sqrt{2}}{327} \right)

s=91.7 m     (3 s.f.)s = 91.7 \ \mathrm{m \ \ \ \ \ } (\mathrm{3 \ s.f.})


For max height:\mathrm{For \ max \ height}:

Max s at v=0;\mathrm{Max \ s \ at} \ v=0;

v2=u2+2asv^2 = u^2 + 2as

0=(30sin45)2+2(9.81)(s)0 = (30 \sin 45^{\circ})^2 + 2(-9.81)(s)

s=22.9 m     (3 s.f.)s = 22.9 \ \mathrm{m \ \ \ \ \ } (\mathrm{3 \ s.f.})


:mmm:


:rofl: people don't be scared, once you know the theory it's all good :yy:
Reply 5678
Original post by Vionar
No, I'm saying that you couldn't beat the joint forces of budey and aurororororae!


Ahh such faith! Haha im sure I could... With fishy in the background.


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Reply 5679
Original post by L'Evil Fish
:rofl: people don't be scared, once you know the theory it's all good :yy:


LMAO. Was just about to say that's the reason behind nightmares.


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