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C3 help needed please

Vorsah

Need help with Q14 A

Using product rule I got dy/dx= 3(x+1)^2(2x-1)^4 + 8(2x-1)^3(x+1)^3

Need help from here

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Reply 1

krisshP

Original post by Vorsah

Need help with Q14 A

Using product rule I got dy/dx= 3(x+1)^2(2x-1)^4 + 8(2x-1)^3(x+1)^3

Need help from here

dy/dx = v[du/dx] - u[dv/dx]
=[(2x-1)^4][3(x+1)^2][1] - [(x+1)^3][4(2x-1)^3][2]
=3[(x+1)^2][(2x-1)^4] - 8[(x+1)^3][(2x-1)^3]

Try factorising as (x+1)^2 is a common factor as well as (2x-1)^3 :smile:

(edited 10 years ago)

Reply 2

Vorsah

Original post by krisshP

dy/dx = v[du/dx] - u[dv/dx]
=[(2x-1)^4][3(x+1)^2][1] - [(x+1)^3][4(2x-1)^3][2]
=3[(x+1)^2][(2x-1)^4] - 8[(x+1)^3][(2x-1)^3]

Try factorising as (x+1)^2 is a common factor as well as (2x-1)^3 :smile:

Thanks

Reply 3

krisshP