a) think of an ammonium ion? It is dative covalent bonding a PH3 molecule is trigonal pyramidal in shape. Bond angle of 107' When a proton comes along, the PH3 will donate it's lone pair of electrons to the proton and dative covalently bonds therefore the new bond angle is 109.5, ygm?
Anyone doing ocr A wanna help each other with course works practicals message me I've done a 2 of each so far but I'm aiming for 80% so need some help!
For Edexcel AS Chemistry are there certain practicals we need to know for the exams? I've seen the crystals one come up a few times in the past papers I've done, are there any more?
For the 'Green Chemistry' topic of the Unit 2 Exam in AS OCR A, how much detail do we need to go into? Im a little lost as to whether we need to know lots of examples etc.
Thanks
The question which seems to crop up a lot over the past years has been how catalytic converters work - Absorption of CO and NO which weakens the bonds (held onto the metal surface), by the metal surface of the converter. Bonds form with the metal surface, these hold the gas molecules in the correct position for a reaction to occur. These are then Desorbed by the surface, releasing C02 and N2.
Can someone explain the displacement reactions for the halogens. Is the reason why bromine cannot displace chlorine due to chlorine being more reactive than it. Also when bromine displaces say potassium iodide do you get an orange or brown solution?
A more reactive halogen displaces a weaker halogen, that's the essential theory - this is known as a Displacement reaction as you've said. And so, Chlorine can displace both Br2 and I2, Br2 can only displace I2, whereas I2 can't displace anything as said halogens are more reactive. Br2 + 2I- -> 2Br- + I2 To detect the presence of Iodine, in water it would be brown and in cyclohexane it would be violet.
Can someone please give me a step by step guideline on how to predict the shapes and bond angles in molecules and ions? I find this really difficult and the book only confuses me
Okay, a bit of exam technique; Always mention the number of bonded and lone pairs. Always mention that if a molecule only has bonded pairs the electron pair repulsion is equally and this causes the molecule to spread out as far as possible. And always mention, lone pairs repel more than electron pairs.
This is the tedious bit, this is just a case of remembering all the different shapes and bond angles. They'll give you a molecule, it may help to draw a Dot and Cross diagram of the covalent bonds. Then, correspond the number of bonded and lone pairs to the molecule characteristics below: Linear - 2 double bonds, bond angle of 180. Trigonal Planar - 3 bonded pairs, bond angle of 120. Tetrahedral - 4 bonded pairs, bond angle of 109.5. Octahedral - 6 bonded pairs, bond angle of 90. Pyramidal - 3 bonded pairs and 1 lone pair, bond angle of 107. Non-linear - 2 bonded pairs and 2 lone pairs, bond angle of 104.5.
Hello! I'm doing edexcel chemistry Does anyone have any notes or link to videos on naming organic compounds? Or is someone able to explain it? I'm so bad at this yet everyone tells me how easy it is!
Hello! I'm doing edexcel chemistry Does anyone have any notes or link to videos on naming organic compounds? Or is someone able to explain it? I'm so bad at this yet everyone tells me how easy it is!
The trick with nomenclature is to practice.I also used to be horrible at nomenclature and failed my nomenclature class test.But then I did tons of organic chemistry and nomenclature, so after a while it just became second nature to me. You MUST be good at nomenclature or else you will FAIL organic chemistry part of AS Chemistry, since alot of the questions you msut be able to draw or identify the organic compounds mentioned in the question. Practice make sperfect.Either you conquer nomenclature or it will conquer you.
Ahh, this could be useful, I jsut posted another thread before i came across this one!
I'm resitting OCR F322 and am just working on some revision posters, but I can't find my notes from last year on all the different mechanisms I need to know, the only one I can remember for certain is Radical Substitution but I know there's more!
If someone could remind me of the others I'd be really grateful!
Ahh, this could be useful, I jsut posted another thread before i came across this one!
I'm resitting OCR F322 and am just working on some revision posters, but I can't find my notes from last year on all the different mechanisms I need to know, the only one I can remember for certain is Radical Substitution but I know there's more!
If someone could remind me of the others I'd be really grateful!
Thank you!!
It is split into 4 modules Module 1 (Basic organic chemistry concepts and hydrocarbons): Nomenclature, Subsitution reactions,Isomers and stereoisomers,Polymers,Atom economy and Percentage Yield,Alkenes (The reactions, properties,its double bond and uses),Alkanes and everything I mentioned for alkenes apply to its except the double bond bit,Fossil fuels,Bond fission , and petroleum.
Module 2 (Alcohols,halogenoalkanes and analysis) : Alcohol and their uses Reactions of alcohols Oxidising Alcohols Esterifiication and Esters Halogenoalkanes Infrared spectroscopy and Mass spectroscopy
Module 3(Energy)nthalpy Changes Bond Enthalpies Measuring Enthalpy Changes Hess Law Reaction rates and collision theory Catalysts Reversible reactions Boltzmann Maxwell Distribution Chemical equilibrium Equilibrium and Industry Haber process
Module 4 (Resources): The greenhouse effect and global warming(Learn the link between the two and remember ENHANCED greenhouse effect causes global warming) Climate change The ozone layer Ozone depletion Green chemistry Air pollution CO2,from villain to saviour(Hint:Basically just learn CO2 uses in Industry and how its obtained as a byprodut of fermentation). Hope this helps
It is split into 4 modules Module 1 (Basic organic chemistry concepts and hydrocarbons): Nomenclature, Subsitution reactions,Isomers and stereoisomers,Polymers,Atom economy and Percentage Yield,Alkenes (The reactions, properties,its double bond and uses),Alkanes and everything I mentioned for alkenes apply to its except the double bond bit,Fossil fuels,Bond fission , and petroleum.
Substitution reactions, that's what I'm missing! Thanks
I don't get the whole bit with the colour of solution. What does that show. From the book it says something about 'the two colourless starting materials react to produce the red-brown colour of bromine'
And on the chemrevise sheet is says the free halogen is represented by the colour of solution. Which says yellow for bromine.
Right a query with my aqa textbook. Surely the oxidising ability if halogens decrease as you go down a group.
Also I don't get the whole bit with the colour of solution. What does that show. From the book it says something about 'the two colourless starting materials react to produce the red-brown colour of bromine'
And on the chemrevise sheet is says the free halogen is represented by the colour of solution. Which says yellow for bromine.
Really confused. Thanks
The colour of the solution at the end indicates the halogen present after a displacement reaction, for example, bromine in water is orange in colour, whereas chlorine in water is pale-green and iodine is brown.
So, the use of this ionic equation might be helpful: Cl2 + 2Br- -> Br2 + 2Cl-, so the chlorine halogen displaces the bromide, forming chloride and bromine. The colour changes will indicate what is present essentially. The solution can either be added to Water or Cyclohexane - cyclohexane gives a more clear result as the colour changes of Br2 and I2 are very similar in water (Orange and Brown), whereas in Cyclohexane Br2 goes Orange and I2 goes Violet.
The colour of the solution at the end indicates the halogen present after a displacement reaction, for example, bromine in water is orange in colour, whereas chlorine in water is pale-green and iodine is brown.So, the use of this ionic equation might be helpful:Cl2 + 2Br- -> Br2 + 2Cl-, so the chlorine halogen displaces the bromide, forming chloride and bromine. The colour changes will indicate what is present essentially. The solution can either be added to Water or Cyclohexane - cyclohexane gives a more clear result as the colour changes of Br2 and I2 are very similar in water (Orange and Brown), whereas in Cyclohexane Br2 goes Orange and I2 goes Violet.Hope that helped.
the bit about the colours I don't get. When chlorine displaces bromine surely the free halogen is bromine. Which the sheet says you get a yellow solution. But you're saying something about orange/brown.
the bit about the colours I don't get. When chlorine displaces bromine surely the free halogen is bromine. Which the sheet says you get a yellow solution. But you're saying something about orange/brown.
That's where the sheet is wrong, the free halogen is bromine and so the colour in water and cyclohexane would be Orange. Let me try and get a picture from my textbook.
To summarise, its always the free halogen after the displacement reaction has occurred which determines the colour of the solution.
Cl2 = Pale-green in both water and cyclohexane. Br2 = Orange in both water and cyclohexane. I2 = Brown in water and Violet in cyclohexane.