Guys/girls, this question has been bothering me for a while now, would really like some help, would be much appreciated.
0.85g of an indigestion tablet containing calcium hydroxide was was reacted with 50cm3 of 1.00M hydrochloric acid. the resulting solution was made up to 250m3 in a volumetric flask. 25cm3 of this solution required 30.80cm3 of 0.100M sodium hydroxide for neutralisation. calculate the per cent purity, by mass of the calcium hydroxide.
So I calculated the moles of sodium Hydroxide, by using n= cv, so n = (0.100 x 30.80/1000) =0.00308 Moles
NaOH + HCL -> Nacl + H20, so they react 1:1, the moles of HCl must also equal 0.00308 moles.
but now what do I do?