Super HARD C3 question.

Thank you in advance.

Are you sure this is C3? It is easily provable (took some thinking) with the tan compound angle formula, but I don't know how to solve this in C3 terms (then again, I don't know the spec and compound angles could be in C3). Also, it is definitely correct - check with a calculator - I just can't think how to prove it otherwise which is kinda bothering me :/

Are you sure this is C3? It is easily provable (took some thinking) with the tan compound angle formula, but I don't know how to solve this in C3 terms (then again, I don't know the spec and compound angles could be in C3). Also, it is definitely correct - check with a calculator - I just can't think how to prove it otherwise which is kinda bothering me :/

Yes its definitely C3. Shall i send the answer? Maybe that can help to explain it..??

That uses the compound angle formula but without saying it is. I don't remember being taught that as just a standalone rule so I'm guessing you were expected to know the compound angle formulae :/

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So is it not C3? It came up in one of the C3 elmwood papers in doing.. Is it further maths or something

Can you still explain it to me..

x

x

The angle $\theta$ between two lines of gradients $m_1, m_2$ is given by:

$tan\theta = |\dfrac{m_1 - m_2}{1+m_1m_2}|$

But that's literally an abstraction of the tan double angle formula. Are there any exam boards which have that on the spec then?

Thank you in advance.

Where is this question from?

an Emwood paper ...

Are the papers any good?

I've heard IYGB papers are good. Solomon, Elmwood etc. all wish they could be as good as IYGB.

I will give you 50% of what I earn from them ...