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Will the real TeeEm please stand up!

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Original post by physicsmaths
Cant the ans be in a better form like 2^n(n!)^2/(2n+1)!
This was identical to a reduction given in step III 2015 q 1.
Posted from TSR Mobile

I think this is right.

2n+1n!(n+1)!(2n+2)!=22nn!(n+1)n!(2n+2)(2n+1)!=2nn!n!(2n+1)!=2n(n!)2(2n+1)!\displaystyle \frac{2^{n+1}n!(n+1)!}{(2n+2)!}=\frac{2\cdot 2^n n!(n+1)n!}{(2n+2)(2n+1)!}=\frac{2^n n! n!}{(2n+1)!}=\frac{2^n(n!)^2}{(2n+1)!}
(edited 8 years ago)
Original post by TeeEm
39 days to A level results

Question for Sunday 05/07/15
AS Level Maths upwards


Here is my solution. Take n=1 and it shud give 2/3 but your formula gives 1/3. All you are missing is that 2^n+1 should be 2^2n+1. And then you answer simplifies to my one!
ImageUploadedByStudent Room1436090242.733018.jpg


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Original post by rayquaza17
I think this is right.

2n+1n!(n+1)!(2n+2)!=22nn!(n+1)n!(2n+2)(2n+1)!=2nn!n!(2n+1)!=2n(n!)2(2n+1)!\displaystyle \frac{2^{n+1}n!(n+1)!}{(2n+2)!}=\frac{2\cdot 2^n n!(n+1)n!}{(2n+2)(2n+1)!}=\frac{2^n n! n!}{(2n+1)!}=\frac{2^n(n!)^2}{(2n+1)!}


Yh thats it. I just cant do latex as it wouldve been clearer.


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Reply 623
Original post by physicsmaths
Yh thats it. I just cant do latex as it wouldve been clearer.


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maybe there is a typo in my answer. This is my answer also
Original post by TeeEm
maybe there is a typo in my answer. This is my answer also


But do you agree now that your answer simplifies to my one roght?


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Original post by TeeEm
maybe there is a typo in my answer. This is my answer also


Also you should steal this ImageUploadedByStudent Room1436091498.982642.jpg
IIT JEE question. Very weird and neat answer.


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Reply 626
Original post by physicsmaths
But do you agree now that your answer simplifies to my one roght?


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definitely
I could not understand what you were saying last night without latex.
(I refuse to use latex too)
Reply 627
Original post by physicsmaths
Also you should steal this ImageUploadedByStudent Room1436091498.982642.jpg
IIT JEE question. Very weird and neat answer.


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probably I have it somewhere already.
by the way the recurrence relation is an old question of mine from my proof by induction sheet and not stolen
Original post by TeeEm
probably I have it somewhere already.
by the way the recurrence relation is an old question of mine from my proof by induction sheet and not stolen


Oh no i wasnt implying you stole that just you always say 'i shall steal this' so thought this question was nice.
There are so many questions like that or sinilar that onvolve the even and odd terms like that.


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Reply 629
Original post by rayquaza17
I think this is right.
2n+1n!(n+1)!(2n+2)!=22nn!(n+1)n!(2n+2)(2n+1)!=2nn!n!(2n+1)!=2n(n!)2(2n+1)!\displaystyle \frac{2^{n+1}n!(n+1)!}{(2n+2)!}=\frac{2\cdot 2^n n!(n+1)n!}{(2n+2)(2n+1)!}=\frac{2^n n! n!}{(2n+1)!}=\frac{2^n(n!)^2}{(2n+1)!}


Original post by physicsmaths
Here is my solution. Take n=1 and it shud give 2/3 but your formula gives 1/3. All you are missing is that 2^n+1 should be 2^2n+1. And then you answer simplifies to my one!
ImageUploadedByStudent Room1436090242.733018.jpg
Posted from TSR Mobile



the answer is all wrong as I copied and pasted and have not changed the answer...
I rewrote the question today after I did the solution and did it as a show.
Original post by TeeEm
the answer is all wrong as I copied and pasted and have not changed the answer...
I rewrote the question today after I did the solution and did it as a show.


My fonal answer is wrong?????


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Reply 631
Original post by physicsmaths
My fonal answer is wrong?????


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mine was wrong because I have 2 very similar questions to the one I posted.
I decided to make a new one, copied and pasted, and forgot to change the answer in the box. I just put the solution up to check yours.
Reply 632
38 days to A level results

Question for Monday 06/07/15
AS Level Maths upwards
(edited 8 years ago)
Original post by TeeEm
the answer is all wrong as I copied and pasted and have not changed the answer...
I rewrote the question today after I did the solution and did it as a show.

I never worked through the question, I was just checking if your two answers were the same. :redface:
Reply 634
37 days to A level results

Question for Tuesday 07/07/15
A Level Maths upwards
(edited 8 years ago)
Original post by TeeEm
37 days to A level results

Question for Tuesday 07/07/15
AS Level Maths upwards


This mustve been stolen from aea paper 14....


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Reply 636
Original post by physicsmaths
This mustve been stolen from aea paper 14....


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Nope,
stolen may be but these are standard parametric loci of evolutes, involutes, epicycloids etc which I have tons of examples!
Original post by TeeEm
Nope,
stolen may be but these are standard parametric loci of evolutes, involutes, epicycloids etc which I have tons of examples!


Ah i see. I had only seen it first time in aea you see.


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Reply 638
Original post by physicsmaths
Ah i see. I had only seen it first time in aea you see.


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look at IYGB, C4,

Paper T, Q6
Paper S, Q9

very easy to make for a question maker of my calibre ....
Reply 639
Original post by TeeEm
look at IYGB, C4,

Paper T, Q6
Paper S, Q9

very easy to make for a question maker of my calibre ....


Hi TeeEm,

Have you got any good resources on Laplace transforms and any of these:

Probability ( rms, density functions and random variables)
Central limit theorem
Regression
Weibull distribution
Normal distribution

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