Sorry, my computer has been messing me around. Please find attached the photo...
Given that this curve crosses the x-axis at a point X, we may deduce that when y=0,x=X⟹(X,0)
likewise: x=0,y=Y⟹(0,Y)
Then you want to find the values of the variable t for y = 0 and x = 0 respectively
If the t3+1=0 is the part that is confusing you, let f(x)=t3+1 and notice that f(−1)=(−1)3+1=0 does this give you a clue how to factorise this expression?
Given that this curve crosses the x-axis at a point X, we may deduce that when y=0,x=X⟹(X,0)
likewise: x=0,y=Y⟹(0,Y)
Then you want to find the values of the variable t for y = 0 and x = 0 respectively
If the t3+1=0 is the part that is confusing you, let f(x)=t3+1 and notice that f(−1)=(−1)3+1=0 does this give you a clue how to factorise this expression?
Hmm, I am still stuck. After working out the value of 't' when y = 0, I can't seem to work out the value of 'q' for which I keep on getting as 0. Any chance of you showing me some working? Because I've been stuck on this question for ages now.
Hmm, I am still stuck. After working out the value of 't' when y = 0, I can't seem to work out the value of 'q' for which I keep on getting as 0. Any chance of you showing me some working? Because I've been stuck on this question for ages now.
Do let me know if the answer is different or if I made a mistake though! (It's been a long day)
Do let me know if the answer is different or if I made a mistake though! (It's been a long day)
No, there has been no mistake. Thank you very much for your all of your help, it makes a lot more sense now.
I have managed to attempt the question and I got the exact same answer as you which is '8/3'. I have verified this with the answer book and it is correct!
No, there has been no mistake. Thank you very much for your all of your help, it makes a lot more sense now.
I have managed to attempt the question and I got the exact same answer as you which is '8/3'. I have verified this with the answer book and it is correct!