Edexcel Unit 1 (IAL): Physics on the Go, WPH01 (24th May 2016)

Reply 20

khassan

2

Original post by djmans

unit 3 forum was way more active

Can you send me a link to the unit 3 forum

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Reply 21

djmans

2

Original post by khassan

Can you send me a link to the unit 3 forum

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its already over

Reply 22

daddydevil

2

So i saw a question in qp asking to find the horizontal distance travelled by a projectile at an angle. I used the range equation but the mark scheme used another format. Like v=s/t and finding t from vertical speed.

But using the range formula, will i get full mark? Answer did match.

Reply 23

Komol

2

Need help for question no a(ii) thanx

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Reply 24

khassan

2

Original post by djmans

its already over

Yea, I did that paper..wanted to check my answers

Reply 25

Sulzaae

Original post by Saad69

How to calculate part ii?

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i just saw the thread i think u have to use 1/2fx or Kx^2(K x squared) they are both supposed to give the same answer...it gives the energy stored in the spring

Reply 26

Sulzaae

Original post by Komol

Need help for question no a(ii) thanx

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I'm sorry the picture is inverted but what my teacher said is that the
maximum force the truck will have is 576N which is lower than the friction therefore the lorries acceleration is limited

Reply 27

Komol

2

Original post by Sulzaae

I'm sorry the picture is inverted but what my teacher said is that the
maximum force the truck will have is 576N which is lower than the friction therefore the lorries acceleration is limited

Thanx.....

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Reply 28

AlvlVictim

OP

9

Jan 2014 IAL question 17 whole question help
@EUSHA @Sulzaae @djmans
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(edited 7 years ago)

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Reply 29

Dr.strange12

2

Original post by Komol

Need help for question no a(ii) thanx

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Simply when the truck accelerates, the box to stay on it must accelerate at the same rate. In order to do so there must be a force accelerating the box at the same rate as the truck. This the friction. The friction is 630N max.So the max acceleration of the box must be 630 dividied by 200kg the mass of the box. Which is therefore the max acceleration of the trucck

Reply 30

Komol

2

Original post by Dr.strange12

Simply when the truck accelerates, the box to stay on it must accelerate at the same rate. In order to do so there must be a force accelerating the box at the same rate as the truck. This the friction. The friction is 630N max.So the max acceleration of the box must be 630 dividied by 200kg the mass of the box. Which is therefore the max acceleration of the trucck

Thanks.....

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Reply 31

djmans

2

Original post by Saad69

Jan 2014 IAL question 17 whole question help
@EUSHA @Sulzaae @djmans
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the graph is correct, in the calculation you must find the gradient of the 2nd graph use the middle part to find the gradient

Reply 32

AlvlVictim

OP

9

Original post by Saad69

How to calculate part ii?

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In case anyone wondering this is how to solve it it was only extended to 3.4 cm

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Reply 33

edexcelruinedme

1

Is it just my school where physics is just a train wreck compared to all the other subjects?

Reply 34

AlvlVictim

OP

9

The paper was tough
Hoping for low boundaries
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Reply 35

Komol

2

Original post by Saad69

The paper was tough
Hoping for low boundaries
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Yea it was i didnt ans all of them for the time limit damn....

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Reply 36

its_samuel

3

I thought so too. Stuggled with the Stoke's law question where you find the radius of the raindrop at terminal velocity, and the Vector Diagram question

Original post by Komol

Yea it was i didnt ans all of them for the time limit damn....

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Reply 37

EUSHA

2

Original post by its_samuel

I thought so too. Stuggled with the Stoke's law question where you find the radius of the raindrop at terminal velocity, and the Vector Diagram question

radius of the raindrop at terminal velocity?which one was that?

Reply 38

EUSHA

2

no unofficial mark scheme?

Reply 39

Rumpelstiltskin_

Did any1 else get 7.9x10^-14 ohm metres for the resistivity on the last q?

And did any1 get 0.77 for the efficiency of the electric motor q? The current and voltage were given along with the mass and height the weight was lifted by...

Edexcel Unit 1 (IAL): Physics on the Go, WPH01 (24th May 2016)

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