Official OCR A2 G484 June 2016 [Module 1] [90UMS]

1.02x10^33 lol idk

What were your values for S2 people??? I NEED TO KNOW FUSUFBAKFJKDNDKIDJFJ

No, the equation for c was (gmh)/(m x change in temperature),so the masses cancelled out, so C was independent of mass in this case.

You should have added the vertical component of the water hose hopefully you should get some marks for the use of the component however, maybe drop 1 or 2 marks.

Did anyone get 1.73 x 10^33 for the mass of S2?

Thats what i thought, but surely, when the mass is doubled, the energy is doubled (mgh) so wouldnt the temperature increase aswell? I understand the equation obviously shows that temperature changeshouldnt increase, but i cannot understand how this is the case in a physical way.

Guys can u tell me why is it 1070?
(92+8.25sin55)×9.81 then i got 969

One full wavelength is 2pie (360)

Guys can u tell me why is it 1070?
(92+8.25sin55)×9.81 then i got 969

I know this isn't hugely helpful but here are my solutions nonetheless....

5.78
3.46
0.609
8.25
1071
3.93 (5pi/4)
0.471
0.666
6.413*10^23
0.925
23.3*10^3
1.2*10^12
3.6*10^12
5.98*10^4
6.43*10^31
131
4.88.63
11323

for the fireman question, i calculated the weight of the fireman and took away the vertical component of the water hose so i got around 830N i think

Thats what i thought, but surely, when the mass is doubled, the energy is doubled (mgh) so wouldnt the temperature increase aswell? I understand the equation obviously shows that temperature changeshouldnt increase, but i cannot understand how this is the case in a physical way.

The mass of S2 was 1.03 * 10^33

Thats what i thought, but surely, when the mass is doubled, the energy is doubled (mgh) so wouldnt the temperature increase aswell? I understand the equation obviously shows that temperature changeshouldnt increase, but i cannot understand how this is the case in a physical way.