Official OCR A2 G484 June 2016 [Module 1] [90UMS]

@teachercol are you still making mark scheme for this??
love ya

- probably tomorrow. I'm teaching all aft and out this eve.
Done the paper.

anyone got a rough idea of the questions with marks? just want to see how many I've lost.. thanks

- probably tomorrow. I'm teaching all aft and out this eve.
Done the paper.

Graph question about ball:

One mark for why gradient is the same

Two marks for why areas of triangles are not equal

One mark for speed of impact with ground

Two marks for Speed at D

One mark for height of first bounce

One mark for Newtons First law

2 marks for why forces on Newtons 3rd law are same

2 marks for why forces on Newtons 3rd law are different

3 Marks for firemans hose question

2 Marks for KE EPE Graph

2 Marks for Max speed

2 marks for time period

1 mark for newtons gravitational law with symbols

1 mark for centripetal force with symbols

2 marks for the r1 r2 m1 m2 ratio equation

4 marks for the SHC of lead balls

2 marks for how internal energy is effected by temperature

2 marks for assumptions of tube flipping experiment

2 marks for how temp change if mass is doubled

3 marks for radius of 21 and s2

3 marks? for mass of s2

2 marks for volume of partially inflated balloon

3 marks for moles needed to be released

2 marks for gravitational field strength above surface of mars

2 marks for mass of mars

One mark for stating keplers third law

One mark for how you would expect speed of mars's moon to change if it got closer to mars

That comes to 52 marks, I can't remember the rest, sorry.

No worries mate thanks! Did you have say that internal energy is directly proportional? or is it enough to say as temp increases IE increases?

Are u retarded last years exam was much easier and was 43 for an a u spaz

Yh basically point c is the common centre of mass. so all the weight appears to act from there, hence why the planets orbit around that point. So consider at point C there is a large star of mass ( m1+m2) and then you use keplars law and centripetal force to work out m2(s2)

Graph question about ball:

One mark for why gradient is the same

Two marks for why areas of triangles are not equal

One mark for speed of impact with ground

Two marks for Speed at D

One mark for height of first bounce

One mark for Newtons First law

2 marks for why forces on Newtons 3rd law are same

2 marks for why forces on Newtons 3rd law are different

3 Marks for firemans hose question

2 Marks for KE EPE Graph

2 Marks for Max speed

2 marks for time period

1 mark for newtons gravitational law with symbols

1 mark for centripetal force with symbols

2 marks for the r1 r2 m1 m2 ratio equation

4 marks for the SHC of lead balls

2 marks for how internal energy is effected by temperature

2 marks for assumptions of tube flipping experiment

2 marks for how temp change if mass is doubled

3 marks for radius of 21 and s2

3 marks? for mass of s2

2 marks for volume of partially inflated balloon

3 marks for moles needed to be released

2 marks for gravitational field strength above surface of mars

2 marks for mass of mars

One mark for stating keplers third law

One mark for how you would expect speed of mars's moon to change if it got closer to mars

That comes to 52 marks, I can't remember the rest, sorry.

Is that right? I cant see how the mass of s2 exerts any force on S2. It just changes the radius of the orbit.

TeacherCol, could you put my mind at ease for the Mass of S2?
I used keplers third law and rearranged to make M the subject
(4pi^2*(3.6*10^12)^3)/((6.67*10^-11)*(86400*365*4)^2)= 1.73*10^33
Dear god pleas be right.

Well I think it's fair that A* at 46. I would say cap is 52. Mathematical papers suit maths students. There are also papers that go against maths students (wordy crap), so this evens out. I found the paper very straight forward.

You don't have to lie to make your dick look bigger. You have most likely got every calculation wrong and is right now in shell shock, it's ok but I'll guide you to your DDU triple Alevel combo you brain drama student.

No, the vertical component of the contact force is equal to the weight of the fireman plus the vertical component of the impulse of the water. Answer = 92g + 8.25*(whatever the speed of the water was)*sin(55)