Original post by hassantsr
Can someone explain why this is an even function?
f(x)= ln(1+x^2)
f(x)= ln(1+x^2)
Well, what is the condition for a function to be even? Does that condition apply here?
Original post by RDKGames
Well, what is the condition for a function to be even? Does that condition apply here?
f(-x)=f(x) if it is an even function so it is an even function right?
Original post by hassantsr
f(-x)=f(x) if it is an even function so it is an even function right?
Show that it is to convince yourself.
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