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(maths) am i doing this right so far?

am i doing this right? it just looks wrong?
please walk me through what to do from here
i know the picture looks bad but yh lol

i'm just confused i thought it's rearrange then substitute but idk



No substituting K will not be the correct approach. Try and substitute y = kx/2 + 1 into the first equation.
You will then end up with a quadratic in the first equation.
The question then specifies that they intersect once so can you now see what to do next?
(edited 5 years ago)
so i make them equal to each other and then solve...? @Rohan77642


Original post by rainclouds-
so i make them equal to each other and then solve...? @Rohan77642



yes make them equal to eachother, make 1 side = 0, solve for K.
for B - since you already have what K is, you can substitute it into the equations
Original post by Rohan77642
No substituting K will not be the correct approach. Try and substitute y = -kx/2 - 1 into the first equation.
You will then end up with a quadratic in the first equation.
The question then specifies that they intersect once so can you now see what to do next?


Isn't it y = kx/2 + 1?
Original post by rainclouds-
so i make them equal to each other and then solve...? @Rohan77642




Not exactly solve. You now have a quadratic in x. You know that there is only 1 intersection point, therefore that means that there is only one value of x. This means what about a quadratic?

Spoiler

(edited 5 years ago)
Original post by 3pointonefour
Isn't it y = kx/2 + 1?


Yes sorry. Corrected. :smile:
Original post by rainclouds-
so i make them equal to each other and then solve...? @Rohan77642




Sorry, I made a mistake, the substitution should be y = kx/2 + 1
Original post by rainclouds-
am i doing this right? it just looks wrong?
please walk me through what to do from here
i know the picture looks bad but yh lol

i'm just confused i thought it's rearrange then substitute but idk





Basics, pal. There is nothing a ‘mathematical’ about this question. You just make the two equations equal.
Umm...

Make y (of the bottom equation) the subject, and you get, y= 1+kx/2.
Then substitute this y in the first equation and work through it.
Original post by rainclouds-
am i doing this right? it just looks wrong?
please walk me through what to do from here
i know the picture looks bad but yh lol

i'm just confused i thought it's rearrange then substitute but idk



lmaoooo its ok i got it i got the answer

tysm guys free reps 4 all
Original post by rainclouds-
lmaoooo its ok i got it i got the answer

tysm guys free reps 4 all


You are wrong- none of the replies including mine was on the right path.

The rational as follows

Step 1: You make the two equations equal

Step 2: simplify and organise so you can clearly see what A, B and C are

Step 3: think , in order for a quadratic equation to have only one root (meaning only one solution) the DISCRIMINANT must be 0
Therefore workout the K values that makes the discriminant 0
Original post by MathsLove
You are wrong- none of the replies including mine was on the right path.

The rational as follows

Step 1: You make the two equations equal

Step 2: simplify and organise so you can clearly see what A, B and C are

Step 3: think , in order for a quadratic equation to have only one root (meaning only one solution) the DISCRIMINANT must be 0
Therefore workout the K values that makes the discriminant 0


no i mean i crossed it all out and did the question again. it's alright i'll make a note of it in my book anyway i appreciate the support
Original post by rainclouds-
no i mean i crossed it all out and did the question again. it's alright i'll make a note of it in my book anyway i appreciate the support


Did you get the idea, though. It doesn’t explicit tell you the discriminant is 0 instead it tells “it intersects at one”

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