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Need help with maths

4D7FA27D-D172-4F32-BC55-1295F10E9B93.jpeg
Original post by Matheen1
4D7FA27D-D172-4F32-BC55-1295F10E9B93.jpeg

How far have you got?
Reply 2
Original post by Muttley79
How far have you got?

A6BA09C2-E3F2-4C66-AB94-753AF98E4BE3.jpeg I think I’ve found the two tangents
Original post by Matheen1
4D7FA27D-D172-4F32-BC55-1295F10E9B93.jpeg

1. differentiate equation
2. equate the differentiated equation to 4 as u wanna find the x coordinates for the gradient (if that makes sense?)
3. then once u have your x coordinates sub these into original equation
4. now u must have a gradient (of 4) and 2 coordinates and form te equations
Original post by Matheen1
A6BA09C2-E3F2-4C66-AB94-753AF98E4BE3.jpeg I think I’ve found the two tangents

The first three lines are correct but when you put dy/dx = 4 you need to collect the '4' on the right to get a quadratic = 0. Only then can you solve ...
Reply 5
Original post by Muttley79
The first three lines are correct but when you put dy/dx = 4 you need to collect the '4' on the right to get a quadratic = 0. Only then can you solve ...

4D099277-22D1-4C85-9726-64AD37AD4E19.jpeg Is this correct (corrections are in green)!
Original post by Matheen1
Is this correct (corrections are in green)!

Check the 'c' in the x = 2 tangent
Reply 7
Original post by Muttley79
Check the 'c' in the x = 2 tangent

Oh thanks I just realised it’s meant to be -11 instead of 11.
Original post by Matheen1
Oh thanks I just realised it’s meant to be -11 instead of 11.

Yes - looks OK now

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