# helpWatch

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#1
Can someone explain to me how you do part iii) of this question, all the previous answer I'm sure are correct so use them if needed.
0
#2
I'm begging the exam is tomorrow, I need help
0
13 years ago
#3
The distance the bus travels ahead of car=240+uT+0.5aT²
=240+20T+0.1T²

240+20T-0.1T²=distance travelled by car=15T (deceleration=negative acceleration)

That means that 240+20T-0.1T²=15T
So 0.1T²-5T-240=0
Divide by 0.1: T²-50T-2400=0
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#4
should it not be +5t instead of minus
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#5
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