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Maths C3 Logarithms Help

Hey everyone,

I'm stuck on this question:
Find as natural logarithms, the roots of the equation.
2e^x + 3e^-1 = 7

I don't even know where to start?
Please help me!

Thank you :smile:
Reply 1
Original post by theworldnow
Hey everyone,

I'm stuck on this question:
Find as natural logarithms, the roots of the equation.
2e^x + 3e^-1 = 7


I don't even know where to start?
Please help me!

Thank you :smile:


multiply everything by e^x and then you will get a quadratic and solve the quad
Reply 2
Original post by ajayhp
multiply everything by e^x and then you will get a quadratic and solve the quad


Thank you I understand now!

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