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    Test whether the given point lies on the straight line (or curve) with the given equation.

    (p, (p-1)^2 + 1) on y = x^2 - 2x + 2

    (p-1)^2 + 1 = p^2 - 2p + 2

    p^2 + 1 + 1 = p^2 - 2p + 2

    p^2 = p^2 - 2p

    The point does not satisfy the equation.

    Where am I going wrong? :confused:
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    (Original post by goodgrief)
    Test whether the given point lies on the straight line (or curve) with the given equation.

    (p, (p-1)^2 + 1) on y = x^2 - 2x + 2

    (p-1)^2 + 1 = p^2 - 2p + 2

    p^2 + 1 + 1 = p^2 - 2p + 2

    p^2 = p^2 - 2p

    The point does not satisfy the equation.

    Where am I going wrong? :confused:

    (p,(p-1)^2+1)=(p,p^2-2p+2)

    Edit: I see you had that. You have the answer in your second line. Not sure what you're doing after that.

    Oh I see now. (p-1)^2 is not p^2+1. Multiply out (p-1)(p-1).
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    (Original post by BabyMaths)
    (p,(p-1)^2+1)=(p,p^2-2p+2)
    My brain is not awake today. Thank you!
 
 
 
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