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Solving a quadratic simultaneous equation

How would you solve:
= 4x
y = x
Reply 1
Original post by beth_page
How would you solve:
= 4x
y = x


Square the equation in the bottom
y^2 = x^2
So if y^2= 4x and also y^2=x^2
Then 4x=x^2
So x^2 - 4x=0
x(x-4)=0
So y=0 and x=0 which is trivial but also x=4
So x=4 and y=4
(edited 8 years ago)

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