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Find when these parametic curves cross the x and y axis:

1) x = 1 - cos(t) , y= sin(t)

2) x= sin(t) y=cos(t)^2

obviously you sub when x=0 and when y=0 in.
Original post by Improvement
Find when these parametic curves cross the x and y axis:

1) x = 1 - cos(t) , y= sin(t)

2) x= sin(t) y=cos(t)^2

obviously you sub when x=0 and when y=0 in.


Good job!
Reply 2
Original post by Improvement
Find when these parametic curves cross the x and y axis:

1) x = 1 - cos(t) , y= sin(t)

2) x= sin(t) y=cos(t)^2

obviously you sub when x=0 and when y=0 in.


Just rearrange and solve for t when x or y=0.
Reply 3
Original post by B_9710
Just rearrange and solve for t when x or y=0.


okay I have been trying that must of messing that up :smile:
Original post by Improvement
Find when these parametic curves cross the x and y axis:

1) x = 1 - cos(t) , y= sin(t)

2) x= sin(t) y=cos(t)^2

obviously you sub when x=0 and when y=0 in.


1) y-axis: x=0 so cos(t)=1 so t=0. y=sin(0)=0, so (0,0).
x-axis: y=0 so sin(t)=0 so t=0 or pi. Gives (0,0) and (2,0).

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