M1 Jan 2006 q6iii

Hi

Can someone please explain why the answers to 6iii are that a) R is below B and b) 1 N ?

Thanks

(I have attached the question paper)

Combined QP - M1 OCR.pdf680.0KB

Original post by JAVM

Hi

Can someone please explain why the answers to 6iii are that a) R is below B and b) 1 N ?

Thanks

(I have attached the question paper)

When P=0 there is no horizontal force acting on the ring therefore it is in the same vertical alignment as A and B. Then considering the fact that the length of the string is 0.7m and the distance between A and B is less than that, it is a logical deduction that R must be below B.

For the tension, just balance the vertical components. Tension going up, weight going down.

Reply 2

JAVM

OP

Original post by RDKGames

When P=0 there is no horizontal force acting on the ring therefore it is in the same vertical alignment as A and B. Then considering the fact that the length of the string is 0.7m and the distance between A and B is less than that, it is a logical deduction that R must be below B.

For the tension, just balance the vertical components. Tension going up, weight going down.

Thanks for the reply.

Is it that the R 'slides down' the string?

Original post by JAVM

Thanks for the reply.

Is it that the R 'slides down' the string?

If you want to think of it that way, sure. But the idea is that the string's length is greater than the distance AB so when the ring slides down the string, the string will be taut, and the system will be in equilibrium such that the string goes downwards from A, through B, through the ring, then comes back up to B again as that's where it is attached to. So that's why R is below B when considering lengths, and why it's just a 1 mark question.

M1 Jan 2006 q6iii

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