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Past Exam Question help!

An electrical current flows through a wire and does 333 J of work every second causing the temperature of the wire to increase. After some time, the temperature of the wire stops increasing. The current is then switched off and the wire cools. Calculate q, w and ΔU per second at the following times:

(i) Switch on.

(ii) After some time.

(iii) Switch off.

Would (i) and (iii) have the same answer?
So, t = 0, therefore, it is isothermal.
Delta U = q + w = 0 and so q = -w which is 0

and (ii) After some time

w = 333J
dU = dq - pdV
At constant volume, Delta U = q
And delta U = Cv delta T

I'm not sure how to carry on from here

Thank you!