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Re: Further maths forces help desperately needed

really hard question which i dont understand anything about please help

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Original post by amin11234
really hard question which i dont understand anything about please help


P=0 is your usual particle on a slope question. First thing you want to do is label the weight and resolve it parallel/perpendicular to the slope. It is in equilibrium therefore you need to use the fact that the frictional force, μR\mu R, is the greater than or equal to the force dragging it down, which is the weight component parallel to the slope.

Second part is straight-forward with the P being resolved parallel/perpendicular - you should be able to do this. Then the second part of this question just asks you to calculate moments about the bottom-right corner of the box in Figure 2.

For third part, you need to use the fact that the overall moment is 0 about the same point.
Reply 2
Original post by RDKGames
P=0 is your usual particle on a slope question. First thing you want to do is label the weight and resolve it parallel/perpendicular to the slope. It is in equilibrium therefore you need to use the fact that the frictional force, μR\mu R, is the greater than or equal to the force dragging it down, which is the weight component parallel to the slope.

Second part is straight-forward with the P being resolved parallel/perpendicular - you should be able to do this. Then the second part of this question just asks you to calculate moments about the bottom-right corner of the box in Figure 2.

For third part, you need to use the fact that the overall moment is 0 about the same point.


could you draw the diagram for part (ii) please. im not quite sure how to get the answer to that one.

thank you
Reply 3
Original post by RDKGames
P=0 is your usual particle on a slope question. First thing you want to do is label the weight and resolve it parallel/perpendicular to the slope. It is in equilibrium therefore you need to use the fact that the frictional force, μR\mu R, is the greater than or equal to the force dragging it down, which is the weight component parallel to the slope.

Second part is straight-forward with the P being resolved parallel/perpendicular - you should be able to do this. Then the second part of this question just asks you to calculate moments about the bottom-right corner of the box in Figure 2.

For third part, you need to use the fact that the overall moment is 0 about the same point.


i got (27/25)P=235.2 for part (ii) and im not sure if it is correct. What did you get?

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