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I'm really struggling with this question, if someone could help it would be really appreciated. Thanks :smile:

The diagram shows an enclosure in the shape of a rectangle with dimensions 2x meters by y meters joined to an isosceles right-angled triangle with hypotenuse 2x meters. The enclosure has perimeter P meters and area A square meters.

a) (i) Express A in terms of x and y.
(ii) Express P in terms of x and y.

b) It is given that the perimeter of the enclosure is 100 meters.
(i) show that A=100x-(1+2√2)x^2
Reply 1
hi is it possible to post a photo or diagram?
Reply 2
idk how to do that its just a house shape with 2x on the bottom and y on the side, the isosceles sits on top of the rectangle
Original post by penguin2412
idk how to do that its just a house shape with 2x on the bottom and y on the side, the isosceles sits on top of the rectangle


It's an isosceles right-angle triangle. Meaning the two perpendicular sides of the triangle are both equal length. In fact, if you say that they are aa then we must have the property a2+a2=(2x)2a^2+a^2 = (2x)^2 which implies that a=x2a=x\sqrt{2}.

So just find the perimeter and area of the house in terms of x and y

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