Original post by TehJokur
Then dy/dx = 3
How..?
Original post by TehJokur
Find the coordinates of the stationary point on the curve
x = t^2+1
y = 1+4t-t^2
So far I've got dx/dt = 2t and dy/dt = 4-2t
Then dy/dx = 3
x = t^2+1
y = 1+4t-t^2
So far I've got dx/dt = 2t and dy/dt = 4-2t
Then dy/dx = 3
bless
Quick Reply
Related discussions
- Not My Problem, It's yours!
- Is it possible to immediately enter another uni for the second year?
- yahoo email problems
- Studying a PhD degree while living in a different city - the Visa Question
- Images don’t always load
- Retaking 2nd year
- Moving countries mid A Levels
- Dating apps are boring and soulless
- How do i improve physics problem solving?
- Please help with this question!
- I ****ed up; really struggled with Sixth Form and now sat at home doing nothing.
- People stare rudely at me.
- deemed medically unfit!?
- degree choice help
- Late Portfolio submission to UAL
- Transfer to Another Uni
- Header buttons not working properly
- Late Portfolio submission to UAL
- Boyfriend problems
- ucas website down?
Latest
Trending
Last reply 3 days ago
Did Cambridge maths students find maths and further maths a level very easy?Last reply 2 weeks ago
Edexcel A Level Mathematics Paper 2 unofficial mark scheme correct me if wrongMaths
71
Trending
Last reply 3 days ago
Did Cambridge maths students find maths and further maths a level very easy?Last reply 2 weeks ago
Edexcel A Level Mathematics Paper 2 unofficial mark scheme correct me if wrongMaths
71
