C3 Last Minute Questions Thread (Edexcel 1 day to go!)

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Sir Cumference
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Hi everyone :wavey:

June is fast approaching which means that the C3 exam is getting closer. The "Last Minute" threads were popular last year so we're bringing them back for 2018!

This thread is a place to ask any C3 question you have so whatever your question, please post it here and someone will be able to help you out Image This could be an exam question from AQA, Edexcel, OCR or it could just be a general question about a particular topic.

When posting a question, make sure you post your attempt so that helpers know where you're stuck and can help you faster.

You can look through last year's thread which may help with your revision.

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Kevin De Bruyne
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:bump:
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ckfeister
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Guessing from C1, C2 resit exams for AQA I predict its going to be toughest its been this year with a lot of traps and twists
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rhaegar444
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this cohort seems a lot let enthusiastic to use TSR it looks like
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ihatePE
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this discrimination against WJEC tutu tut
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JJWood
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Probably really simple but slightly confused what they've done here! (This is Q5 from June 2017):

I understand it all apart from how they managed to get 3x+10 on the top? When I work it out I get x = ln(10/(3x+1)) so basically missing that 3x on the top!

Any help appreciated, thanks!
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Sir Cumference
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(Original post by JJWood)
Probably really simple but slightly confused what they've done here! (This is Q5 from June 2017):

I understand it all apart from how they managed to get 3x+10 on the top? When I work it out I get x = ln(10/(3x+1)) so basically missing that 3x on the top!

Any help appreciated, thanks!
So are you saying you don't understand how they got from the second to the third line? If not, it's probably best if you post your working.
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RDKGames
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(Original post by JJWood)
Probably really simple but slightly confused what they've done here! (This is Q5 from June 2017):

I understand it all apart from how they managed to get 3x+10 on the top? When I work it out I get x = ln(10/(3x+1)) so basically missing that 3x on the top!

Any help appreciated, thanks!
Rewrite 1 = \dfrac{3x+1}{3x+1}
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TheYearNiner
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(Original post by RDKGames)
Rewrite 1 = \dfrac{3x+1}{3x+1}
How do I remember how to draaw sine inverse and cos inverse? and tan inverse? I know its too late to ask but can ya help a brother out
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Sir Cumference
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(Original post by TheYearNiner)
How do I remember how to draaw sine inverse and cos inverse? and tan inverse? I know its too late to ask but can ya help a brother out
Try this video. If you can follow this method then it's the same method for inverse cos and tan. Or you could try learning them off-by-heart but it is quite late
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Gibbo_
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Does anyone know how to find the range of g(X) when g(X)=x/(x-3) and x>3. It's only 2 marks and the mark scheme doesn't show any working. Thanks
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Sir Cumference
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(Original post by Gibbo_)
Does anyone know how to find the range of g(X) when g(X)=x/(x-3) and x>3. It's only 2 marks and the mark scheme doesn't show any working. Thanks
This is an improper fraction so you can split it using a division method e.g. long division. If you do that you get

1+\frac{3}{x-3}

Does that help?
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Gibbo_
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(Original post by Notnek)
This is an improper fraction so you can split it using a division method e.g. long division. If you do that you get

1+\frac{3}{x-3}

Does that help?
Ah perfect thank you!
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sarahhh16
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is the domain the output of the function and the range is the input? Or is it the other way round? I can never do domain and range ughh
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MclarenP1
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(Original post by Tottiasr10)
I think c3 has been leaked someone report to edexcel
nah it hasnt attention seeker
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Speedbird129
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(Original post by sarahhh16)
is the domain the output of the function and the range is the input? Or is it the other way round? I can never do domain and range ughh
domain = input (x values)

range = output (y values)

Weird but how I remember it is you hit golf balls into the driving 'range' so this is the output and then input x values to get y values so match them up accordingly. Hope this makes sense.

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sarahhh16
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(Original post by Speedbird129)
domain = input (x values)

range = output (y values)

Weird but how I remember it is you hit golf balls into the driving 'range' so this is the output and then input x values to get y values so match them up accordingly. Hope this makes sense.
okay thank youu! Good luck with C3
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Speedbird129
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(Original post by sarahhh16)
okay thank youu! Good luck with C3
Thank you, and you
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nisha.sri
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How do you differentiate y=x^2 lnx / 3 -2x+4
I am having trouble doing x^2lnx/3
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Sir Cumference
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(Original post by nisha.sri)
How do you differentiate y=x^2 lnx / 3 -2x+4
I am having trouble doing x^2lnx/3
For \frac{x^2\ln x}{3} first take out the \frac{1}{3} so you just have to differentiate x^2\ln x. Now try to use the product rule for x^2 and \ln x. Post your working if you get stuck.
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