The Student Room Group

Further Maths Complex Numbers Question

Question:
a)Given that the complex numbers w1 w_{1} and w2 w_{2} are the roots of the equation z2512i=0 z^2-5-12i=0 , express w1 w_{1} and w2 w_{2} in the form of a+ib a +ib where a and b are real

b)i)Indicate the point sets in an argand diagram corresponding to the sets of the complex numbers
A=z:z=3,zϵC A={z:\left | z \right | =3, z \epsilon \mathbb{C}}
B=z:z=2,zϵC B={z:\left | z \right | =2, z \epsilon \mathbb{C}}

ii)Shade the region corresponding to the values of z for which the inequalities
2<z<32 <\left | z \right |<3 and 30<arg(z)<60 30^{\circ}<arg(z)<60^{\circ}

are simultaneously satisfied.


My attempt:
a)
z2512i=0z^2-5-12i=0
z2=5+12iz^2= 5+12i
z=±(5+12i)(0.5)z= \pm (5+12i)^(0.5)
note that (3+2i)2=5+12i(3+2i)^2 = 5+12i
thus z=±(3+2i) z = \pm (3+2i)
w1=3+2iw_{1}= 3+2i
w2=(3+2i)w_{2}= -(3+2i)

b)

i)

A=z:z=3,zϵC A={z:\left | z \right | =3, z \epsilon \mathbb{C}}
B=z:z=2,zϵC B={z:\left | z \right | =2, z \epsilon \mathbb{C}}
C1.jpg



ii)2<z<32 <\left | z \right |<3 and 30<arg(z)<60 30^{\circ}<arg(z)<60^{\circ}
Attachment not found

I shaded the region I thought would be the right answer in purple


The part I am finding difficult is part b. Please help
(edited 5 years ago)
Original post by bigmansouf
...


Where did 33.7 come from?

Your purple region is almost fine, you just need to extend it all the way to the blue line.
Reply 2
arg(z)=23 arg(z) = \frac{2}{3}
α=arctan23=33.69006753=33.7 \alpha = arctan\frac{2}{3} = 33.69006753 ^{\circ} = 33.7 ^{\circ}

Thank you for your help
Original post by RDKGames
Where did 33.7 come from?

Your purple region is almost fine, you just need to extend it all the way to the blue line.
Original post by bigmansouf
arg(z)=23 arg(z) = \frac{2}{3}
α=arctan23=33.69006753=33.7 \alpha = arctan\frac{2}{3} = 33.69006753 ^{\circ} = 33.7 ^{\circ}

Thank you for your help


Part (a) has nothing to do with part (b)
Reply 4
it is an old question from University of London School Examinations Department
Original post by RDKGames
Part (a) has nothing to do with part (b)
Reply 5
it is an old question from University of London School Examinations Department
Original post by RDKGames
Part (a) has nothing to do with part (b)
Reply 6
Original post by RDKGames
Part (a) has nothing to do with part (b)

thank you i managed to do it

Quick Reply

Latest