What do you keep answering wrong?
Original post by Danyal124
Help!!! I understand bronsted lowry acid = H donor and base = h acceptor but keep answering this question wrong
Bronsted Lowry acid = donates a proton
Bronsted Lowry base = accepts a proton
Looking at the first question. Focus on the forward reaction first.
The water (H2O) is accepting a proton (H+) to form H3O+. Since it is accepting a proton, the water is acting as a base.
Look at the reverse reaction in the first question.
The ethanoate ion (CH3COO-) is accepting a proton (H+) to form CH3COOH. Since it accepts a proton, it is a base.
Are you able to follow now? What problems did you face - why did you keep getting it wrong? Try to do parts ii and iii with the same logic.
Original post by qwert7890
Bronsted Lowry acid = donates a proton
Bronsted Lowry base = accepts a proton
Looking at the first question. Focus on the forward reaction first.
The water (H2O) is accepting a proton (H+) to form H3O+. Since it is accepting a proton, the water is acting as a base.
Look at the reverse reaction in the first question.
The ethanoate ion (CH3COO-) is accepting a proton (H+) to form CH3COOH. Since it accepts a proton, it is a base.
Are you able to follow now? What problems did you face - why did you keep getting it wrong? Try to do parts ii and iii with the same logic.
Bronsted Lowry base = accepts a proton
Looking at the first question. Focus on the forward reaction first.
The water (H2O) is accepting a proton (H+) to form H3O+. Since it is accepting a proton, the water is acting as a base.
Look at the reverse reaction in the first question.
The ethanoate ion (CH3COO-) is accepting a proton (H+) to form CH3COOH. Since it accepts a proton, it is a base.
Are you able to follow now? What problems did you face - why did you keep getting it wrong? Try to do parts ii and iii with the same logic.
i see what youre doing but how do you know to use the reverse reaction route
Original post by Danyal124
i see what youre doing but how do you know to use the reverse reaction route
That is what a reversible reaction means...
This is the forward reaction
CH3COOH + H2O ---> CH3COO- + H3O+
This is the backward reaction
CH3COO- + H3O+ ---> CH3COOH + H2O
Instead of writing two separate equations we use one equation with a double arrow:
CH3COOH + H2O <====> CH3COO- + H3O+
Now look at each reaction separately as forward and reverse, and hopefully this helps you? Is it clear now?
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