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UCAT Normal Distribution

I calculated the UCAT normal distribution to roughly equal:
X=(2499,(273.887)^2).

Also calculated last year to be:
x=(2511,(264.523)^2).
Hopefully, this is useful for comparing the previous year's UCAT cut off scores.

Correct me if I am wrong

(edited 2 years ago)

Reply 1

username5319484

Ahh yes, maths. Didn't understand a single bit of it but I commend your effort.

Reply 2

GodlyGod

That is the value for the standard deviation. The higher this value, the more "spread out" the data is.

(edited 2 years ago)

Reply 3

GANFYD

Original post by GodlyGod

That is the value for the standard deviation. The higher this value, the more "spread out" the data is.

The SD was 269.16 for the 2020 sitting, so you are not far out :smile:

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UCAT Normal Distribution

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