i think maybe the ch is the doublet as it sees ch2 but what i don't get is why there is a quartet as i cannot see anywhere in the structure where a proton can see 3 hydrogens
look at the structure. The phenyl protons are pretty obvious, which only leaves 3 left to assign. Think about the coupling constants, there are 3 double doublets.
i think maybe the ch is the doublet as it sees ch2 but what i don't get is why there is a quartet as i cannot see anywhere in the structure where a proton can see 3 hydrogens
Is this for A-level? The rules you learn at A-level won't let you explain the splittings here
Although you are expected to understand geometric isomerism, so it's not a huge leap to see the non-equivalent environments in an alkene for NMR.
When you only know the n+1 rule it might be, to be honest, especially when you need to start talking about the magnitude of J and some more complicated splittings such as double doublets and such
Happy to go through it, but just wanted to make sure the OP knows that it's not really A-level material (if they're doing A-level/equivalent).
When you only know the n+1 rule it might be, to be honest, especially when you need to start talking about the magnitude of J and some more complicated splittings such as double doublets and such
Happy to go through it, but just wanted to make sure the OP knows that it's not really A-level material (if they're doing A-level/equivalent).
Agreed, the degree of sophistication is beyond A' level, but an A' level student should be able to recognise that the protons are in different environments and likely to produce a more complex splitting pattern.