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Edexcel C3,C4 June 2013 Thread

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Reply 4460
Does anyone have the solomon papers on them? I don't understand question 7c from E and question 3b from L - would really appreciate help on how to do them, think they're tricky!
Original post by Mathletic
Would you consider that to be a harder integrand? It doesnt seem clear that thats how ts is done.

Thanks :smile:


I think it would be pretty standard, though I'm not 100% sure about that.

You could also easily integrate it using a substitution like u=x+1, btw.
(edited 10 years ago)
Reply 4462
Original post by Mathletic
Would you consider that to be a harder integrand? It doesnt seem clear that thats how ts is done.

Thanks :smile:


Personally that seems a bit of a weird method to me (well, perfectly valid, but a bit harder to spot). I would just go for algebraic long division.
Original post by justinawe
xx+1\dfrac{x}{x+1}

=x+11x+1= \dfrac{x+1-1}{x+1}

=x+1x+11x+1= \dfrac{x+1}{x+1} - \dfrac{1}{x+1}

=11x+1= 1 - \dfrac{1}{x+1}


xx+1 dx=(11x+1)dx=xln(x+1)+C\therefore \displaystyle \int \dfrac{x}{x+1} \ dx = \int \left( 1 - \dfrac{1}{x+1} \right) dx = x - \ln (x+1) + C


That partial fractions/division method is beautiful. I have no idea why we don't get taught it that way, it's so much faster than long division!

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Reply 4464
(edited 10 years ago)
Original post by wndms
Can anyone please help me with this c4?
Fir part c) I know you have to equate dy/dx to 0. But then what do you do after? The answer is supposed to be (pi,-1). I don't understand .. thanks!

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what paper is this from?
Original post by jokersaurus
I have no idea how to answer any vector questions but I should be okay at getting 70 UMS+ as long as they only ask 1 vector question. Have any past papers asked more than 1 vector question?



Yes only one question per paper...but i have to tell you that vector questions based on many marks...for example last year was 14 marks...!!so you have to study them...:redface:
Reply 4467
Does anyone have a really straight forward method of integration by substitution? Really panicking for tomorrow :frown:


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Original post by Econ1994
Does anyone have the solomon papers on them? I don't understand question 7c from E and question 3b from L - would really appreciate help on how to do them, think they're tricky!


For 3b, think of the formulae for sin(a+b).

Sin(3x+x) = sin3xcosx + cos3xsinx
Sin(3x-x) = sin3xcosx - cos3xsinx

so sin(3x+x) + sin(3x-x) = 2sin3xcosx

Hence 1/2(sin4x +sin2x) is what you integrate. A similar method can be used on other questions with the formula for cos(a+b) as well :smile:.
Good luck everyone! (: Hope this one is millions of times better than C3. No words can describe how awful C3 was, so let's hope for a nice(r) C4!
Original post by jokersaurus
I have no idea how to answer any vector questions but I should be okay at getting 70 UMS+ as long as they only ask 1 vector question. Have any past papers asked more than 1 vector question?


june 2012
One thing I struggle with is vectors and finding the shortest distance, for example part d of this:


ImageUploadedByStudent Room1371482624.331712.jpg

Any help appreciated :smile:


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Original post by Aikta_S
Does anyone have a really straight forward method of integration by substitution? Really panicking for tomorrow :frown:


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Think of it in steps: (1) Let u=a function of x (or whatever the letters are). (2) Differentiate to find dx. (3) Sub in u where appropriate and replace the dx with whatever you found after differentiating u. (4) If there are limits, find out what values of u correspond to the values of x and replace them on the integral. Hope this helped :smile:
Original post by suncake
That partial fractions/division method is beautiful. I have no idea why we don't get taught it that way, it's so much faster than long division!

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I never really bother with long division, unless it's absolutely necessary. There will almost always be an alternative method anyway. Synthetic division is a lot faster and easier for me.
Original post by SortYourLife
One thing I struggle with is vectors and finding the shortest distance, for example part d of this:


ImageUploadedByStudent Room1371482624.331712.jpg

Any help appreciated :smile:


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The shortest distance will always be the line drawn that's perpendicular between the 2 lines. This means the dot product will be 0. Draw it out - sometimes you can use triangle theorems, like when a right-angled triangle is formed :smile:
(edited 10 years ago)
Original post by Zaphod77
The shortest distance will always be the line drawn that's perpendicular between the 2 lines. This means the dot product will be 0. Draw it out - sometimes you can use triangle theorems a right-angled triangle is formed :smile:


Ah right cheers :smile: will have a go it now :biggrin:


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Original post by fayled
How can you give up revising if you never started?


Ok ive done 2 past papers, and couldnt do any of them even with text book, exam soultions tutorials mark schems
so i give up
(edited 10 years ago)
Reply 4477
6. A circular cylinder has a perpendicular height equal to the radius of the base r cm.
Given that the volume of this cylinder is V cm^3


(a) show that V = (pi)r^3
Reply 4478
Original post by Zzzyax
6. A circular cylinder has a perpendicular height equal to the radius of the base r cm.
Given that the volume of this cylinder is V cm^3


(a) show that V = (pi)r^3


V=pir^2h

h=r

so V=pir^3

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