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Edexcel C3,C4 June 2013 Thread

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Original post by orange94
Hey what did I do wrong with this question!! Help !!

ImageUploadedByStudent Room1371490541.662260.jpg


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Nothing, 1 is a constant, c is a constant.
Let them get married :lovie:
Original post by Myocardium
How would you integrate something like 3^x?


3^x/ln(3) + c
Original post by PythianLegume
Hence integrating 3^x leads to division by ln(3).


Original post by Westeros
ax=axlna+C\int a^x = \frac{a^x} {\ln a} +C


Oh I see... What about something like 3^2x?
Original post by PythianLegume
You've integrated it wrong - it looks more like differentiation there.


Ahh brilliant thank you :smile:
Original post by Westeros
The half angle is because you have cos x
So to be able to use the double angle formulae, x must be x/2
so cos2(x/2) = cos x


Original post by justinawe
You want to get rid of the square root, so you need it in terms of something squared.

22cosx\sqrt{2 - 2\cos x}

=22(12sin2x2)= \sqrt{2 - 2(1 - 2\sin^2 \frac{x}{2})}

=22+4sin2x2= \sqrt{2 -2 + 4\sin^2 \frac{x}{2}}

=4sin2x2 = \sqrt{4\sin^2 \frac{x}{2}}

=2sinx2= 2\sin \frac{x}{2}


thank you guys, thank you Justin that makes more sense now :smile:
Does anyone have a copy of the leaked June 2012 C4 Paper and mark scheme?
Original post by lefterispower
please guys i want help with the question 7 c) in the paper of January 2013...:frown:


What don't you understand?

Tip: If you're told that AP is perpendicular to l1, then the dot product must equal 0
arrrrgh! integration is a disaster. :cry: Could somebody please explain integration in brief? ASAP! thanks !
Original post by Myocardium
Oh I see... What about something like 3^2x?


Unparseable latex formula:

3^2^x = (3^2)^x = 9^x

Original post by Myocardium
Oh I see... What about something like 3^2x?


Well y=32x

ln(y) = 2xln(3)
(1/y)(dy/dx)=2ln(3)
dy/dx=2 x 32xln(3)

Hence integration divides by 2ln(3).
Reply 4630
When do you use radians or degrees if the question doesn't tell you??

For example in this question part e (http://gyazo.com/06b6e38f7d8f889efc89c4e44c5478fe) I used degrees and I got the wrong answer. You had to use radians, but it didn't specify it anywhere.
Reply 4631
Original post by sonyeric33
u forgot to find du/dx and sub that in


You mean like this ?

ImageUploadedByStudent Room1371491155.718594.jpg


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Reply 4632
Reply 4633
Original post by lefterispower
please guys i want help with the question 7 c) in the paper of January 2013...:frown:


Form simultaneous equations to find lamda. The two equations can be formed from the dot product of l1 & AP (which are perpendicular so = 0 ) and the other equation you already have, it's the equation of the line l1.

http://www.examsolutions.net/a-level-maths-papers/worked-solution/worked-solution.php?paper_id=407&solution=7.3
Original post by ytop2
photo.jpgphoto.jpgphoto.jpg


can ANYONE please help me solve this equation to get it in terms of V, as I have put at the side :frown: can't do it at all


Multiply by k, Take exponentials, Get rid of the denominator by multiplying through, Expand brackets and take it from there.
Original post by Dev607
When do you use radians or degrees if the question doesn't tell you??

For example in this question part e (http://gyazo.com/06b6e38f7d8f889efc89c4e44c5478fe) I used degrees and I got the wrong answer. You had to use radians, but it didn't specify it anywhere.


With integration and differentiation, it's generally radians. Also, think about the values in that question - if it asks about 2 weeks, when t=2, you're not going to be doing sin of 1 degree.
Say you have something like this... Can you just take out 1/3 as a factor and put it outside the integral?
1371491328619.jpg


Edit: got it

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(edited 10 years ago)
Original post by Westeros
What don't you understand?

Tip: If you're told that AP is perpendicular to l1, then the dot product must equal 0



Yeaa i know that...but i dont know the steps before doing a.b=0

if you have time to write me the solution i would be so happy...:redface:
Original post by PythianLegume
You've integrated it wrong - it looks more like differentiation there.


I still can't get it to work is it possible to do it this way?

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