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Further maths complex numbers

How do show (a+bi)/(a-bi) = c+di and then prove c^2 + d^2=1
Do I realise the denominator first but then what do I do thanks
Reply 1
Original post by Bobby21231
How do show (a+bi)/(a-bi) = c+di and then prove c^2 + d^2=1
Do I realise the denominator first but then what do I do thanks


Yes, you need to make the denominator real by multiplying by the complex conjugate.
Having done so, you need to group real and imaginary terms to label c and d.
Once you've done that a minor computation yields the final result.
Reply 2
Original post by Bobby21231
How do show (a+bi)/(a-bi) = c+di and then prove c^2 + d^2=1
Do I realise the denominator first but then what do I do thanks


Taking the modulus of both sides is the quickest way
Reply 3
Original post by joostan
Yes, you need to make the denominator real by multiplying by the complex conjugate.
Having done so, you need to group real and imaginary terms to label c and d.
Once you've done that a minor computation yields the final result.


Ok I have got (a^2+2abi-b)/(a^2+b) how would I simplif?y this would it be 1-1+2abi I think thus is wrong can you please help? Thankyou
Reply 4
Original post by Bobby21231
Ok I have got (a^2+2abi-b)/(a^2+b) how would I simplif?y this would it be 1-1+2abi I think thus is wrong can you please help? Thankyou


Is that: a2b2+2abia2+b2\dfrac{a^2-b^2+2abi}{a^2+b^2}?
Because if so you are essentially done, you just need to break the fraction into real and imaginary parts, and equate them to c and d.
Reply 5
Original post by joostan
Is that: a2b2+2abia2+b2\dfrac{a^2-b^2+2abi}{a^2+b^2}?
Because if so you are essentially done, you just need to break the fraction into real and imaginary parts, and equate them to c and d.


Ok thankyou very much for your help

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