Edexcel FP1 Thread - 20th May, 2016

https://7cba9babeb0db0ff9468853e0b2d0a80708ec59c.googledrive.com/host/0B1ZiqBksUHNYZGxseFBIQkphV0k/January%202015%20(IAL)%20QP%20-%20F1%20Edexcel.pdf

Guys can someone help me with 6 (i) (b)?

https://7cba9babeb0db0ff9468853e0b2d0a80708ec59c.googledrive.com/host/0B1ZiqBksUHNYZGxseFBIQkphV0k/January%202015%20(IAL)%20QP%20-%20F1%20Edexcel.pdf

Guys can someone help me with 6 (i) (b)?

Yeah I used the matrix rotation formula, and equated the top left elements to get

$\cos \theta = - \frac{\sqrt {3}}{2}$

but then using cos inverse gives me pheta = 150

which would mean an anticlockwise rotation through 150 about O but thats wrong??

As I posted in last year's Edexcel FP1 thread, I have written an Enhanced Examination Paper for both Edexcel and MEI FP1.

It is meant to be a significantly more challenging examination of general concepts specified by different boards. It is fully doable for students with knowledge of standard FP1, C1, and C2 material.

If you can make a good start on all of the questions then you should be on track to a strong A in this module.

Good luck!

https://www.furthermathstutor.co.uk/fp1_enhanced.pdf

Yeah so you find that and using cos (2pi-theta) is the only other valid solution in the range this means theta can also equal 210. Then use the transformation matrix again to find the inverse of sin( -0.5) which gives you -30 degrees which is out of range, so we do 180- this value of theta to get a value in range which also gives 210 degrees so since both equations now equate to theta equals 210 and this is in range this is the answer

I dont get it. So I get theta equals 150. How do you know not accept that answer?
Why do you go looking other solutions?

Because the inverse of sin(-0.5) doesn't equal 150 when you put it in your calculator and the values need to match

Oh I see. Another similar question I did, when comparing all 4 of the elements they all gave me the same angle so I didnt have to look for other solutions.

But for this question since the cos and the sine dont give the same value, I have to find a the value (in range) which matches both ?

Yeah that's it This might help

Ah it makes sense, thanks loads for the help!

Because the inverse of sin(-0.5) doesn't equal 150 when you put it in your calculator and the values need to match

Can someone explain how this is done?
("FP1 is as difficult as F1" i don't think so )

Hi, this is a good one, I think what you need to do when proving something is divisible by a large number (>10 or so) is when you are at the "consider when n=k+1" bit, you substitute away the 7^2k using what you just did for n=k.

Do you see what I mean?

I have found the F1 IAL jan 16 paper but does anyone know where the jan 16 IAL FP1 paper?

many thanks

There is no Jan FP1 paper.