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Chemistry HELP

For the reaction: Ba(OH)2 + 2HNO3 Ba(NO3)2 + 2H2O, if we have 1.00 dm3 of Ba(OH)2 of concentration 0.75 moles dm-3, and 4 moles dm-3 HNO3 what is the volume of HNO3 needed in dm3?

Help please
Reply 1
wtf
Original post by lolu123
wtf


ikr
Reply 3
Original post by Student111123
ikr


is it alevels
Original post by Student111123
For the reaction: Ba(OH)2 + 2HNO3 Ba(NO3)2 + 2H2O, if we have 1.00 dm3 of Ba(OH)2 of concentration 0.75 moles dm-3, and 4 moles dm-3 HNO3 what is the volume of HNO3 needed in dm3?

Help please


I'm assuming this is a titration calculation question.

First calculate how many moles of Ba(OH)2 you have.
Then find the mole ratio of Ba(OH)2 : HNO3 by looking at the symbol equation.
From that, you can find the number of moles of HNO3 you need.
Then since you know the concentration of HNO3 you can find the volume.
Original post by TheMindGarage
I'm assuming this is a titration calculation question.

First calculate how many moles of Ba(OH)2 you have.
Then find the mole ratio of Ba(OH)2 : HNO3 by looking at the symbol equation.
From that, you can find the number of moles of HNO3 you need.
Then since you know the concentration of HNO3 you can find the volume.


How you do dat
Original post by Student111123
For the reaction: Ba(OH)2 + 2HNO3 Ba(NO3)2 + 2H2O, if we have 1.00 dm3 of Ba(OH)2 of concentration 0.75 moles dm-3, and 4 moles dm-3 HNO3 what is the volume of HNO3 needed in dm3?

Help please


moles of Ba(OH)2= concentration x volume = 0.75
the molar ratio of Ba(OH)2: HNO3 is 1:2 from the equation, so there is equal moles
therefore the volume of HNO3 is moles/concentration so (0.75x2)/4=0.375dm3
(edited 6 years ago)
Original post by Carolyne2891
moles of Ba(OH)2= concentration x volume = 0.75
the molar ratio of Ba(OH)2:h:NO3 is 1:1 from the equation, so there is equal moles
therefore the volume of HNO3 is moles/concentration so 0.75/4=0.1875dm3 which seems quite small but yeah...


But the options given to me were:
a) 0.75 dm3
b) 0.075 dm3
c) 0.375 dm3
d) 0.0375 dm3
Original post by Student111123
But the options given to me were:
a) 0.75 dm3
b) 0.075 dm3
c) 0.375 dm3
d) 0.0375 dm3


think it's c from doing (0.75x2)/4?? hahah idk it just works
Original post by Carolyne2891
moles of Ba(OH)2= concentration x volume = 0.75
the molar ratio of Ba(OH)2:h:NO3 is 1:1 from the equation, so there is equal moles
therefore the volume of HNO3 is moles/concentration so 0.75/4=0.1875dm3 which seems quite small but yeah...


Original post by Student111123
For the reaction: Ba(OH)2 + 2HNO3 Ba(NO3)2 + 2H2O, if we have 1.00 dm3 of Ba(OH)2 of concentration 0.75 moles dm-3, and 4 moles dm-3 HNO3 what is the volume of HNO3 needed in dm3?

Help please


Ratio isn't 1:1, it's 1:2 as shown in OP's original balanced equation.
You need twice as many moles of HNO3 as you have Ba(OH)2.
Original post by PengDog:)
a^2+b^2=c^2

I think this might help.


Are you sure you posted on the right thread??

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