For the reaction: Ba(OH)2 + 2HNO3 → Ba(NO3)2 + 2H2O, if we have 1.00 dm3 of Ba(OH)2 of concentration 0.75 moles dm-3, and 4 moles dm-3 HNO3 what is the volume of HNO3 needed in dm3?
For the reaction: Ba(OH)2 + 2HNO3 → Ba(NO3)2 + 2H2O, if we have 1.00 dm3 of Ba(OH)2 of concentration 0.75 moles dm-3, and 4 moles dm-3 HNO3 what is the volume of HNO3 needed in dm3?
Help please
I'm assuming this is a titration calculation question.
First calculate how many moles of Ba(OH)2 you have. Then find the mole ratio of Ba(OH)2 : HNO3 by looking at the symbol equation. From that, you can find the number of moles of HNO3 you need. Then since you know the concentration of HNO3 you can find the volume.
I'm assuming this is a titration calculation question.
First calculate how many moles of Ba(OH)2 you have. Then find the mole ratio of Ba(OH)2 : HNO3 by looking at the symbol equation. From that, you can find the number of moles of HNO3 you need. Then since you know the concentration of HNO3 you can find the volume.
For the reaction: Ba(OH)2 + 2HNO3 → Ba(NO3)2 + 2H2O, if we have 1.00 dm3 of Ba(OH)2 of concentration 0.75 moles dm-3, and 4 moles dm-3 HNO3 what is the volume of HNO3 needed in dm3?
Help please
moles of Ba(OH)2= concentration x volume = 0.75 the molar ratio of Ba(OH)2: HNO3 is 1:2 from the equation, so there is equal moles therefore the volume of HNO3 is moles/concentration so (0.75x2)/4=0.375dm3
moles of Ba(OH)2= concentration x volume = 0.75 the molar ratio of Ba(OH)2NO3 is 1:1 from the equation, so there is equal moles therefore the volume of HNO3 is moles/concentration so 0.75/4=0.1875dm3 which seems quite small but yeah...
But the options given to me were: a) 0.75 dm3 b) 0.075 dm3 c) 0.375 dm3 d) 0.0375 dm3
moles of Ba(OH)2= concentration x volume = 0.75 the molar ratio of Ba(OH)2NO3 is 1:1 from the equation, so there is equal moles therefore the volume of HNO3 is moles/concentration so 0.75/4=0.1875dm3 which seems quite small but yeah...
For the reaction: Ba(OH)2 + 2HNO3 → Ba(NO3)2 + 2H2O, if we have 1.00 dm3 of Ba(OH)2 of concentration 0.75 moles dm-3, and 4 moles dm-3 HNO3 what is the volume of HNO3 needed in dm3?
Help please
Ratio isn't 1:1, it's 1:2 as shown in OP's original balanced equation. You need twice as many moles of HNO3 as you have Ba(OH)2.