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[br]let the distance to the South pole be d, and the angle he makes with the center and the axis is $ \theta $[br]Using cosine rule, $d^{2}= 2\times R^{2}-2\times R^{2} cos(\pi-\theta)$
$\theta<\frac{\pi}{2}$
(\textbf{R can never be reached! Is this a tiny discrepancy or my entire argument is fallacious?}),[br] $$\theta = \frac{x}{R}=1 $$[br]Plug in, $$d^{2}=2\times R^{2}-2\times R^{2} cos(\pi-1)[br] \Rightarrow d= R\times \sqrt{2-2cos(\pi -1)}$$[br][br]
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MPhil Advanced Computer Science Cambridge - 2024 EntryLast reply 2 weeks ago
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MPhil Advanced Computer Science Cambridge - 2024 EntryLast reply 2 weeks ago
Easy Colleges in Cambridge to get in - should this be allowedLast reply 2 weeks ago
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MPhil in Machine Learning and Machine Intelligence at Cambridge 2024Last reply 3 weeks ago
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