The Student Room Group

Help with expanding

Hi, I'm a bit confused with 12(b):



I done part (a), which is:


I don't really know where to start since this expression isn't in the normal form for binomial expansion.
(edited 6 years ago)
Reply 1
Original post by ℓove
Hi, I'm a bit confused with 12(b):



I done part (a), which is:


I don't really know where to start since this expression isn't in the normal form for binomial expansion.

11x=(1x)1\frac{1}{1-x} = (1-x)^{-1}

You should be able to expand it now and then do a similar thing for the other fraction. Please post all your working if you get stuck.
Reply 2
Original post by Notnek
11x=(1x)1\frac{1}{1-x} = (1-x)^{-1}

You should be able to expand it now and then do a similar thing for the other fraction. Please post all your working if you get stuck.


Oh yeahh didn’t of that.

7040DC30-7EFE-40AF-8C24-3B1B8C213872.jpg

How do I expand when there’s a constant outside the brackets?
Original post by ℓove
Oh yeahh didn’t of that.

How do I expand when there’s a constant outside the brackets?


3(12x)1=3[expansion of (12x)1]3(1-2x)^{-1}=3\cdot [\mathrm{expansion \ of \ } (1-2x)^{-1}]
Reply 4
Original post by RDKGames
3(12x)1=3[expansion of (12x)1]3(1-2x)^{-1}=3\cdot [\mathrm{expansion \ of \ } (1-2x)^{-1}]


Ooooohh how did I not think of that!! Thanks I appreciate you replying at 1am.

Quick Reply

Latest