Sulfur dioxide reacts with hydrogen sulfide to form water and sulfur. By considering
the changes in the oxidation numbers of sulfur, it can be deduced that, in this
reaction
A 1 mol of sulfur dioxide oxidizes 2 mol of hydrogen sulfide.
B 1 mol of sulfur dioxide reduces 2 mol of hydrogen sulfide.
C 2 mol of sulfur dioxide oxidizes 1 mol of hydrogen sulfide.
D 2 mol of sulfur dioxide reduces 1 mol of hydrogen sulfide.
How to find the ans?