The Student Room Group
Rearrange the 2nd equation into the form Sin(Theta) = [(y-1)/2] then substitue into x=Sin^2(Theta) :biggrin:
Reply 2
I would say use your trig identities....

or, what speedy stef says.
Reply 3
SilverstarDJ
How do I go about writing a cartesian equation with

x= sin^2 theta
y= 1 + 2sin theta

any tips would be much appreciated

Make sinθsin\theta the subject of each equation.
Reply 4
thanks -- I've got it now

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