Gcse help

Factorise?

two numbers that multiply to gove 3 (the constant term at the end) and add to give 14 (it is 14 because 2 x 7 [7 is from the middle]. and the 2 comes from the 2 in front of the x^2)

I don't know how you're going to remember it, so just make up some weird mnemonic for it.

the answer is (2x - 1) (x-3)

so x= 1/2, 3.

do you want me to explain anything else you're unclear about? quote me so I see reply

Thanks for that! i understand it now
i am now stuck on another question! GRAPHS....... i hate them
it says:
the points A and B have co-ordinates (1, 2) and (5, 8)
find, in the form y=mx+c an equation for the line through both points A and B
...i dont have a clue!

What is m? how do you find it? what is c? how do you find it?

Thanks for that! i understand it now
i am now stuck on another question! GRAPHS....... i hate them
it says:
the points A and B have co-ordinates (1, 2) and (5, 8)
find, in the form y=mx+c an equation for the line through both points A and B
...i dont have a clue!

hmmm you seem to have a good understanding so I'll try and explain it through tsr

you are given two points, (1,2) and (5,8). basically, take the x and y values and put it into gradient formula:

m (gradient) = change in y / change in x so.....

m = 2 - 8 / 1 - 5 = -3/2

then you put that into another formula for the actual equation, because now you have two points and a gradient, so....

formula is: y - y1 = m(x-x1)

which is, by considering only ONE coordiante (gonna take (1,2) it's easier to work with) and the -3/2 gradient, we simply sub in:

y - 2 = -3/2 (x-1)

so... y = -3/2x + 7/2

and done.

seem long, but not really...

You know the forum rules. Don't post full solutions!

oh yeah and my name is aragorn

hmmm you seem to have a good understanding so I'll try and explain it through tsr

you are given two points, (1,2) and (5,8). basically, take the x and y values and put it into gradient formula:

m (gradient) = change in y / change in x so.....

m = 2 - 8 / 1 - 5 = -3/2

then you put that into another formula for the actual equation, because now you have two points and a gradient, so....

formula is: y - y1 = m(x-x1) <<<(equation of line formula, in order to use this we need to have ONE coordiante and a gradient [which we just figured out to be -3/2]

which is, by considering only ONE coordiante (gonna take (1,2) it's easier to work with) and the -3/2 gradient, we simply sub in:

y - 2 = -3/2 (x-1)

so... y = -3/2x + 7/2

and done.

seem long, but not really...

hmmm you seem to have a good understanding so I'll try and explain it through tsr

you are given two points, (1,2) and (5,8). basically, take the x and y values and put it into gradient formula:

m (gradient) = change in y / change in x so.....

m = 2 - 8 / 1 - 5 = -3/2

then you put that into another formula for the actual equation, because now you have two points and a gradient, so....

formula is: y - y1 = m(x-x1) <<<(equation of line formula, in order to use this we need to have ONE coordiante and a gradient [which we just figured out to be -3/2]

which is, by considering only ONE coordiante (gonna take (1,2) it's easier to work with) and the -3/2 gradient, we simply sub in:

y - 2 = -3/2 (x-1)

so... y = -3/2x + 7/2

and done.

seem long, but not really...