ElMoro
Badges: 13
Rep:
?
#1
Report Thread starter 9 years ago
#1
...
5
reply
charco
Badges: 17
Rep:
?
#2
Report 9 years ago
#2
(Original post by ElMoro)
Hiya, right now I'm only in year 11 so I can't answer any of the questions! I would appreciate if someone who does the challenge could keep a record of the questions (and answers) and save them as a pdf so I could look at them next year. Thanks for your time.
The Cambridge website keeps a record of all past months questions with their solutions.
0
reply
ElMoro
Badges: 13
Rep:
?
#3
Report Thread starter 9 years ago
#3
(Original post by charco)
The Cambridge website keeps a record of all past months questions with their solutions.
Could you give me the link, please? I had a look but couldn't find it.
0
reply
charco
Badges: 17
Rep:
?
#4
Report 9 years ago
#4
(Original post by ElMoro)
Could you give me the link, please? I had a look but couldn't find it.
You have to login and go to the archive:

http://www.c3l6.org/challenges/archive
3
reply
ElMoro
Badges: 13
Rep:
?
#5
Report Thread starter 9 years ago
#5
(Original post by charco)
You have to login and go to the archive:

http://www.c3l6.org/challenges/archive
Many thanks!
0
reply
Chuck12
Badges: 0
Rep:
?
#6
Report 9 years ago
#6
has anybody completed the silver level yet?
0
reply
Chuck12
Badges: 0
Rep:
?
#7
Report 9 years ago
#7
has anybody completed the gold level ?
0
reply
charco
Badges: 17
Rep:
?
#8
Report 9 years ago
#8
(Original post by Chuck12)
has anybody completed the gold level ?
Judging by the honours board, at least 100 peeps...
0
reply
ThisIsOurDecision
Badges: 8
Rep:
?
#9
Report 9 years ago
#9
Any tips for the silver question?
Spoiler:
Show
I typed in 'F orbital' and it says 'Getting close', but I can't work out what the answer is meant to be..
1
reply
Chuck12
Badges: 0
Rep:
?
#10
Report 9 years ago
#10
(Original post by charco)
Judging by the honours board, at least 100 peeps...
i realise that! i wanted to know if anyone was going to help
0
reply
a_d_a
Badges: 0
Rep:
?
#11
Report 9 years ago
#11
search for 'the orbitron' and look at the green shapes closely, if you are any further gold is in 100,000s of ml and rostegentum is...well who dosn't like 100'C?
0
reply
786-90
Badges: 0
Rep:
?
#12
Report 9 years ago
#12
no dont...
0
reply
Chuck12
Badges: 0
Rep:
?
#13
Report 9 years ago
#13
(Original post by a_d_a)
search for 'the orbitron' and look at the green shapes closely, if you are any further gold is in 100,000s of ml and rostegentum is...well who dosn't like 100'C?
thanks xx
0
reply
Chuck12
Badges: 0
Rep:
?
#14
Report 9 years ago
#14
(Original post by a_d_a)
search for 'the orbitron' and look at the green shapes closely, if you are any further gold is in 100,000s of ml and rostegentum is...well who dosn't like 100'C?
could you tell me how to work it out... like the process?
0
reply
charco
Badges: 17
Rep:
?
#15
Report 9 years ago
#15
(Original post by Chuck12)
could you tell me how to work it out... like the process?
If you hang on for three more weeks the worked answers will be on the site...
0
reply
lekha2611
Badges: 2
Rep:
?
#16
Report 9 years ago
#16
For the silver question, I've worked out the no. of moles of gold in the mass, but how do I know the molarity of the HCL? thank you!
0
reply
CM23925
Badges: 0
Rep:
?
#17
Report 9 years ago
#17
just finished it today. for the dissolving gold, just search for what the maximum concentration of HCl is. because max conc. will give min volume.
0
reply
Jack-
Badges: 0
Rep:
?
#18
Report 9 years ago
#18
I am stumped by the silver question. It gives me 'getting close', but I cant for the life of me think of anything other than f orbital that it could be
0
reply
Jack-
Badges: 0
Rep:
?
#19
Report 9 years ago
#19
(Original post by Jack-)
I am stumped by the silver question. It gives me 'getting close', but I cant for the life of me think of anything other than f orbital that it could be
Never mind, got it in the end. It took me so long because I left 'orbital' in my answer, and apparently that made it wrong. Quite annoying really.
0
reply
lekha2611
Badges: 2
Rep:
?
#20
Report 9 years ago
#20
Gold Q: Because it's 2 moles of gold for every 2 moles of HCl, do you just work out the moles of gold and carry the number across to use on the HCl - you don't have to divide it to find one mole? None of my figures are being accepted
0
reply
X

Quick Reply

Attached files
Write a reply...
Reply
new posts
Back
to top
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise

How are you finding researching unis for 2021 entry?

I have been able to get all the information I need from online research (70)
18.92%
I have tried virtual events and found them useful (76)
20.54%
I have tried virtual events and did not find them useful (68)
18.38%
I would be interested in trying socially distanced or scaled down in person events (78)
21.08%
I want to but don't know where to start with researching unis for 2021 entry (38)
10.27%
I haven't started researching yet (40)
10.81%

Watched Threads

View All