There was no SUVAT question in the Jan 2011 paper.
By long, I mean a whole section for it, just a possibility considering the lack of SUVAT questions in the Jan 2013 paper.

Reply 85

madrevision

9

can someone explain question 7 part c in the January 13 paper please :s-smilie:

Reply 86

yodawg321

12

Original post by zcanf

Does anyone know the grade boundaries for G481 Jan 2013, what would 48 be?

41/60 for an A.

Reply 87

dakenSoren

2

Original post by madrevision

please do and please if you have time can you add what we might need to know for springs in series as I did not understand this when it was taught :colondollar:

thanks

Hmm, looking at the spec it doesn't mention springs in series or parallel directly, I think they would just want you to know that the spring constant for a system of springs changes if you add/remove some. But if you insist :smile:

the formulas for springs in parallel and series are opposite to the ones for resistances in series and parallel.
i.e. For springs that are side by side like this === Then the new Spring constant is just the sum of the two springs so K_New= K_old1+ K_old2
For springs that are in series like this --spring1---spring2--- Then the new spring constant can be calculated from 1/K_New= 1/K_old1+ 1/K_old2

Reply 88

precious maro

12

Original post by zcanf

Does anyone know the grade boundaries for G481 Jan 2013, what would 48 be?

42 for an A

Reply 89

dakenSoren

2

Also here is the mess of my revision notes for mechanics.
They do not go into SUVAT in detail as I do M1 and also some bits are just extra strange things I was thinking of at the time.
Lastly lots of it is paraphrased from the book and some from Wikipedia.

Mechanics - Physics.docx35.8KB

Reply 90

yodawg321

12

Original post by dakenSoren

Also here is the mess of my revision notes for mechanics.
They do not go into SUVAT in detail as I do M1 and also some bits are just extra strange things I was thinking of at the time.
Lastly lots of it is paraphrased from the book and some from Wikipedia.

Cheers for that, will give it a read before going to bed. For the springs how will you be able to get the new force? The 2 constants times the total extension?

Reply 91

madrevision

9

Original post by dakenSoren

Also here is the mess of my revision notes for mechanics.
They do not go into SUVAT in detail as I do M1 and also some bits are just extra strange things I was thinking of at the time.
Lastly lots of it is paraphrased from the book and some from Wikipedia.

wordy...very well worded and detailed, thank you so much :biggrin:

Reply 92

madrevision

9

Original post by dakenSoren

Hmm, looking at the spec it doesn't mention springs in series or parallel directly, I think they would just want you to know that the spring constant for a system of springs changes if you add/remove some. But if you insist :smile:

the formulas for springs in parallel and series are opposite to the ones for resistances in series and parallel.
i.e. For springs that are side by side like this === Then the new Spring constant is just the sum of the two springs so K_New= K_old1+ K_old2
For springs that are in series like this --spring1---spring2--- Then the new spring constant can be calculated from 1/K_New= 1/K_old1+ 1/K_old2

oh ok cool thanks dude :smile:

Reply 93

dakenSoren

2

Original post by yodawg321

Cheers for that, will give it a read before going to bed. For the springs how will you be able to get the new force? The 2 constants times the total extension?

I still doubt they want you to know the formulas for series/parallel springs but you would use the new spring constant * the extension.
So for parallel it would be F_New= ( K_old1+ K_old2)*extension = (K_New)*Extension.

Whereas for series its F_New= ( 1/K_old1+ 1/K_old2)^{^-1}* extension =
(1/K_Ne_w)^{^-1}* extension

Reply 94

patterson

11

Original post by JASApplications

I've just had a quick look through all the past papers and I don't think the experiment to find the centre of gravity has ever actually come up has it?

look at JAN 09 question 4d) its there. centre of gravity

Reply 95

OllieGCSEs

10

Original post by Piguy

If any of you are interested, I've got my UMS calculator based on last years boundaries, which was about an average series (unlike jan 2013 which was a bit more difficult)

Thank you for taking the time to create this! So this is a prediction of what the grade boundaries for the coursework and papers will be like?

Reply 96

sciencecrazed

Does anyone know where I can find the January 2013 mechanics paper ?? I keep only getting the mark scheme :/

Reply 97

Joseph-

OP

what if i told you, i bypassed the ocr servers and i have the exam paper that we are going to do on monday.

Reply 98

dakenSoren

2

Original post by Joseph-

what if i told you, i bypassed the ocr servers and i have the exam paper that we are going to do on monday.

You're clearly working for OCR and will rat all the people who are going to PM you now. :biggrin:

Reply 99

ss2012

8

Original post by Joseph-

what if i told you, i bypassed the ocr servers and i have the exam paper that we are going to do on monday.

I hope this is a joke:/

Official OCR A G481 mechanics 20th May 2013

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