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# Edexcel C3 - 12.06.06 - The 'how did it go' thread! watch

1. can any1 get hold of the paper?? n then we can post sum answers....
2. um guys?
It kinda said that K>1.

So I found 0.5 my self in the beginning and tried to work out a number greater than 1.
I guess then 1.5 is the answer
3. gayyyyy

For the temperature last bit your supposed to say:
As t tends to infinity "t --> [infinity]", e^-0.05t tends to 0 ("e^-0.05t --> 0), therefore, T --> 400(0) + 25 = 25.

T will never reach 20
4. i got 1/2k too
5. (Original post by Rabite)
I think that's right.

They were talking about the third? Second? part though, where you have to find fg(0.25k) or something.
fg(x)= ln ( [2x+k] + k)
fg(k/4)= ln (3k/2)
That's what i got at least, hope it helps
6. definitely harder than the other two..... i got the iteration wrong, kept putting it into y= and wondering why it was wrong, of course i've now realised it was dy/dx...

there was a lot of stuff in there that wasn't immediately obvious and required some amount of thought...

did others get -3root7/8 at one point and 135 degrees as the only answer at another?
7. k u know 4 question 5, when we had to find out x1 x2..etc, did we have to put it in radians, i think ma cal was in deg. do u rekon i'd get any marks?
8. PS. argh ****. "instead of turning point" i wrote "root". penis weed.
oh poooo, I did the same!
I thought the paper was harder than the last 2, and different from all the solomon papers - there seemed to be a lot of emphasis on graph sketching. So annoying with the sin2A, I was sitting there thinking that I could have done that 2 years ago, but the whole obtuse angle thing stumped me.. I managed a couple of lines of working though and got something bizzarre like -root (63/64) as the answer - but just got that thru putting it all in the claculator....wonder if theyll give me any marks, cos it is right!.... shame I havent learnt C4 yet !!

xxx
9. i found this paper MUCH harder than the two past ones. C4 has to be good
was the rate question -1.64

i left it as -1.64 and didnt write it decreases at a rate of 1.64 per minute

will i lose a mark? i believe i may have lost a comfortable 15 marks on the paper.
10. (Original post by sebbie)
definitely harder than the other two..... i got the iteration wrong, kept putting it into y= and wondering why it was wrong, of course i've now realised it was dy/dx...

there was a lot of stuff in there that wasn't immediately obvious and required some amount of thought...

did others get -3root7/8 at one point and 135 degrees as the only answer at another?
I agree with the 135 degree angle question, however I got (+3root7)/8, as sin was also positive in the domain given with the cos value. Therefore [email protected]@ is also positive
11. (Original post by 3.14159265)
i found this paper MUCH harder than the two past ones. C4 has to be good
was the rate question -1.64

i left it as -1.64 and didnt write it decreases at a rate of 1.64 per minute

will i lose a mark? i believe i may have lost a comfortable 15 marks on the paper.
So long as you indicated the temperature decreased at this rate, the question asked you to give the answer in terms of degrees C/min, so unless you did that and put -1.64 degrees C/min I'm guessing you'd lose probably just one mark for incorrect sign
12. reakon i lost a good 25 marks , really wasnt a great paper. First 4 questions were ok, then managed to do bits of the rest, just fell to piecestowards the end
13. Let's just hope the boundaries are lowering lol.
That's our only hope. Well my only hope
14. (Original post by Warren_Sullivan)
I agree with the 135 degree angle question, however I got (+3root7)/8, as sin was also positive in the domain given with the cos value. Therefore [email protected]@ is also positive
A was between 270 and 360

therefore 2A between 540 and 720

sin is negative in that range....
15. (Original post by Warren_Sullivan)
I agree with the 135 degree angle question, however I got (+3root7)/8, as sin was also positive in the domain given with the cos value. Therefore [email protected]@ is also positive
however sin was not positive becuase it was the 4th quadrant.
16. (Original post by franks)
oh poooo, I did the same!
Yeah I did that too, argh. But hopefully it won't matter since it's f'(x) - the gradient that's changing sign - so it would be a root since the gradient is 0 at the turning point...well hopefully anyway.
17. for the 1.64 aswer, i wrote
(-) cm gap then 1.64

will they still knock of a mark for it?
18. (Original post by r3m0t)
Duh, if T >= 25, then T >= 20. THey probably did it because they thought that in other papers, people looked at the answer and worked backwards.
I interpreted the question wrong. It said why cant T reach 20, I was like "hmm thats obv you cant evaluate ln(negative)" but then I thought WHY didnt they say why cant T<25. I thought it was trying to catch me out. Luckily I just put T=20, you got ln(negative) showed you cant evaluate ln(negative) and just left it at that.
19. cos @= 3/4
therefore, by drawing a right angled triangle...
sin @= (root7)/4 (also positive)
[email protected]= [email protected]@= 2.(root7).1/4.3.1/4= (3root7)/8
?
20. That was a joke, it was soooooo hard. My trig isnt up ot scratch and the only part of that I know is when u have the R involved. That didnt come up! GRRRR. I will be happy with a D lol. ( ps was hoping for C or B)

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