The graph f(x) = ax^2 + bx + c has a gradient of 12 at (4, 21) and a stationary point at x=1. Find the values of a, b and c. Please help me with this question. Any suggestions would be greatly appreciated. If you have any suggestions, please explain and illustrate explicitly so I understand. Thank you.
The graph f(x) = ax^2 + bx + c has a gradient of 12 at (4, 21) and a stationary point at x=1. Find the values of a, b and c. Please help me with this question. Any suggestions would be greatly appreciated. If you have any suggestions, please explain and illustrate explicitly so I understand. Thank you.
A good place to start would be differentiating f(x).
The graph f(x) = ax^2 + bx + c has a gradient of 12 at (4, 21) and a stationary point at x=1. Find the values of a, b and c. Please help me with this question. Any suggestions would be greatly appreciated. If you have any suggestions, please explain and illustrate explicitly so I understand. Thank you.
Substitute x=4 into the equation, which will equal 21. Then differentiate f(x), substitute x=1 and make this =0. You'll have two simultaneous equations and should be able to work out the rest from there.
Substitute x=4 into the equation, which will equal 21. Then differentiate f(x), substitute x=1 and make this =0. You'll have two simultaneous equations and should be able to work out the rest from there.
Following your suggestion I get:
Substituting x=4 into original equation and making it equal to 21 f(x) = ax^2 + bx + c 21 = 16a + 4b + c 0 = 16a +4b + c - 21
Differentiation of f(x), substitution of x=1 and making it equal 0 f(x) = ax^2 + bx + c f ' (x) = 2ax + b 0 = 2a + b
It cannot be solved simultaneously because of the third variable c. Are you suggesting to ignore c or am I correct?
Substituting x=4 into original equation and making it equal to 21 f(x) = ax^2 + bx + c 21 = 16a + 4b + c 0 = 16a +4b + c - 21
Differentiation of f(x), substitution of x=1 and making it equal 0 f(x) = ax^2 + bx + c f ' (x) = 2ax + b 0 = 2a + b
It cannot be solved simultaneously because of the third variable c. Are you suggesting to ignore c or am I correct?
Oops sorry, I missed a step.
Differentiate f(x) to get f'(x)= 2ax + b Substitute x=4, which =12 Substitute x=1 to get 2a + b =0 These are the simultaneous equations which you use to get the value of a and b. Into f(x) substitute x=4 and f(x)=21 to get the value of c
Differentiate f(x) to get f'(x)= 2ax + b Substitute x=4, which =12 Substitute x=1 to get 2a + b =0 These are the simultaneous equations which you use to get the value of a and b. Into f(x) substitute x=4 and f(x)=21 to get the value of c