hi, im kinda stuck on this please could anyone help and show the steps on how to solve this correctly:
When Betty is on holiday she intends to go for a five-mile run before breakfast every day. however sometimes she stays in bed instead. the probability that she will go for a run on the first morning is 0.8. thereafter, the probability that she will go for a run is 0.7 if she went for a run on the previous morning and 0.6 if she did not.
Find the probability that on the first three days of her holiday she will go for:
a) three runs
b) exactly two runs
thanks !!!!