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    If you have a continuous uniform distribution with range of 1-2
    wot is P(X=1.5)???

    is it 0?

    also when u say u r using this model do u say X ~ U (1,2)??
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    (Original post by lgs98jonee)
    If you have a continuous uniform distribution with range of 1-2
    wot is P(X=1.5)???

    is it 0?

    also when u say u r using this model do u say X ~ U (1,2)??
    I dont think you represent the distribution like that, i think it's just f(x) = 1/(b-a) [beta minus alpha]

    I'm not so sure on the first question...
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    (Original post by lgs98jonee)
    If you have a continuous uniform distribution with range of 1-2
    wot is P(X=1.5)???

    is it 0?

    also when u say u r using this model do u say X ~ U (1,2)??

    Draw a rectangle and label the bottom corners 1 and 2. The whole area of the rectangle is equal to so the base is 1. So the height must be 1 aswell. The area of the shaded regionis the probaility in this case its

    0.5 x1 so the probability is 0.5

    Its eaier to explain if you draw the diagram.
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    Well probability of all values of x will be the same between alpha and beta wont they?
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    (Original post by Naomi)
    Well probability of all values of x will be the same between alpha and beta wont they?
    How do you mean?
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    (Original post by lgs98jonee)
    If you have a continuous uniform distribution with range of 1-2 wot is P(X=1.5)???
    It's zero. Proof: For all k with 0 < k < 1 we have

    0 <= P(X = 1.5) <= P(1.5 - k/2 < X < 1.5 + k/2) = k.
    (Original post by lgs98jonee)
    also when u say u r using this model do u say X ~ U (1,2)??
    Yes.
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    (Original post by Jonny W)
    It's zero. Proof: For all k with 0 < k < 0.5 we have

    0 <= P(X = 1.5) <= P(1.5 - k/2 < X < 1.5 + k/2) = k.

    Yes.
    tx was pretty sure about those...others didnt seem to have a clue
 
 
 
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