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# Continuous uniform q watch

1. If you have a continuous uniform distribution with range of 1-2
wot is P(X=1.5)???

is it 0?

also when u say u r using this model do u say X ~ U (1,2)??
2. (Original post by lgs98jonee)
If you have a continuous uniform distribution with range of 1-2
wot is P(X=1.5)???

is it 0?

also when u say u r using this model do u say X ~ U (1,2)??
I dont think you represent the distribution like that, i think it's just f(x) = 1/(b-a) [beta minus alpha]

I'm not so sure on the first question...
3. (Original post by lgs98jonee)
If you have a continuous uniform distribution with range of 1-2
wot is P(X=1.5)???

is it 0?

also when u say u r using this model do u say X ~ U (1,2)??

Draw a rectangle and label the bottom corners 1 and 2. The whole area of the rectangle is equal to so the base is 1. So the height must be 1 aswell. The area of the shaded regionis the probaility in this case its

0.5 x1 so the probability is 0.5

Its eaier to explain if you draw the diagram.
4. Well probability of all values of x will be the same between alpha and beta wont they?
5. (Original post by Naomi)
Well probability of all values of x will be the same between alpha and beta wont they?
How do you mean?
6. (Original post by lgs98jonee)
If you have a continuous uniform distribution with range of 1-2 wot is P(X=1.5)???
It's zero. Proof: For all k with 0 < k < 1 we have

0 <= P(X = 1.5) <= P(1.5 - k/2 < X < 1.5 + k/2) = k.
(Original post by lgs98jonee)
also when u say u r using this model do u say X ~ U (1,2)??
Yes.
7. (Original post by Jonny W)
It's zero. Proof: For all k with 0 < k < 0.5 we have

0 <= P(X = 1.5) <= P(1.5 - k/2 < X < 1.5 + k/2) = k.

Yes.
tx was pretty sure about those...others didnt seem to have a clue

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