Hey there! Sign in to join this conversationNew here? Join for free
    • Thread Starter
    Offline

    2
    ReputationRep:
    Name:  Screenshot_2016-04-29-02-04-08-1.png
Views: 43
Size:  92.7 KB
    Part C
    Take the faulty

    headlamp as lamp A, and the lamp which is affected by this as lamp B.

    lamp B 'takes' a greater portion of the voltage in order to overcome its greater resistance. Now taking a greater share of the voltage, it is brighter (P= V^2 / R).

    On the other hand, now having the greater resistance, less current flows through B. This means it now has less power (P= I^2 *R).


    HOW SHOULD I GO ABOUTT?
    PLEASE HELP SOMEONEE
 
 
 
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • Poll
    Would you like to hibernate through the winter months?
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

    Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

    Quick reply
    Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.