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# Hard logs watch

1. 5^3w-1 = 4^250
2. (Original post by SmartFailure)
5^3w-1 = 4^250
Hm yes, this question makes sense. Before we do your homework for you answer me this: what have you tried and also, is the question this:
5^(3w-1) = 4^250
or this:
(5^3w)-1 = 4^250
3. 5^(3w-1) = 4^250

I've tried doing:

log(5)^3w-1 = log(4)^250
log (5)^3w-1 - log (4)^250 = 0
log (5^3w-1 / 4^250) = 0

Don't know where to go from here
4. (Original post by SmartFailure)
5^(3w-1) = 4^250

I've tried doing:

log(5)^3w-1 = log(4)^250
log (5)^3w-1 - log (4)^250 = 0
log (5^3w-1 / 4^250) = 0

Don't know where to go from here
Go back to step one.
5. is this right:

(3w-1)log(5) = 250log(4)

3w-1 = 250xlog(4) / log(5)

3w - 1 = 215.33
3w = 216.33
w = 72.11
6. (Original post by SmartFailure)
is this right:

(3w-1)log(5) = 250log(4)

3w-1 = 250xlog(4) / log(5)

3w - 1 = 215.33
3w = 216.33
w = 72.11
Give the exact form, unless it asks for the approximation. Overall, yes that's right.
7. The only way to calculate this is: 250xlog(4) / log(5) is by calculator right?
8. (Original post by SmartFailure)
The only way to calculate this is: 250xlog(4) / log(5) is by calculator right?
No need, just leave it in its exact form.
9. Alright thanks for the help

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