When 4.50 g of ethanoic acid and 10.0 g of ethanol were allowed to reach equilibrium at 60°C, the equilibrium mixture was found to contain 4.40 g of ethyl ethanoate. Calculate the percentage yield of ethyl ethanoate, based on ethanoic acid. Show your working where necessary.
the answers is 66.7%. I dont understand how to get it . pls help.
When 4.50 g of ethanoic acid and 10.0 g of ethanol were allowed to reach equilibrium at 60°C, the equilibrium mixture was found to contain 4.40 g of ethyl ethanoate. Calculate the percentage yield of ethyl ethanoate, based on ethanoic acid. Show your working where necessary.
the answers is 66.7%. I dont understand how to get it . pls help.
This question is not about organic chemistry, it is stoichiometry and equilibrium using an example from organic chemistry.
Set out your equation with initial moles and then equilibrium moles. Use these values to calculate the % yield